336" - You are to times all of them together to get your answer. Dont forget to put the inches.
Answer:
Mean = 75
Median = 73.5
Mode = 95
Range = 36
Step-by-step explanation:
Given:
Sort:
To find:
Mean:
![\displaystyle \large{\dfrac{1}{n}\sum_{i =1}^n x_i = \dfrac{x_1+x_2+x_3+...+x_n}{n}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7B%5Cdfrac%7B1%7D%7Bn%7D%5Csum_%7Bi%20%3D1%7D%5En%20x_i%20%3D%20%5Cdfrac%7Bx_1%2Bx_2%2Bx_3%2B...%2Bx_n%7D%7Bn%7D%7D)
Sum of all data divides by amount.
![\displaystyle \large{\dfrac{59+60+70+77+89+95}{6}=\dfrac{450}{6}}\\\\\displaystyle \large{\therefore mean=75}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7B%5Cdfrac%7B59%2B60%2B70%2B77%2B89%2B95%7D%7B6%7D%3D%5Cdfrac%7B450%7D%7B6%7D%7D%5C%5C%5C%5C%5Cdisplaystyle%20%5Clarge%7B%5Ctherefore%20mean%3D75%7D)
Therefore, mean = 75
Median:
If it’s exact middle then that’s the median. However, if two data or values happen to be in <em>middle</em>:
![\displaystyle \large{\dfrac{x_1+x_2}{2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7B%5Cdfrac%7Bx_1%2Bx_2%7D%7B2%7D%7D)
From 59,60,70,77,89,95, since 70 and 77 are in middle:
![\displaystyle \large{\dfrac{70+77}{2} = \dfrac{147}{2}}\\\displaystyle \large{\therefore median = 73.5}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7B%5Cdfrac%7B70%2B77%7D%7B2%7D%20%3D%20%5Cdfrac%7B147%7D%7B2%7D%7D%5C%5C%5Cdisplaystyle%20%5Clarge%7B%5Ctherefore%20median%20%3D%2073.5%7D)
Therefore, median = 73.5
Mode:
The highest value or/and the highest amount of data. Mode can have more than one.
From sorted data, there are no repetitive data nor same data. Consider the highest value:
Therefore, mode = 95
Range:
or highest value - lowest value
Thus:
![\displaystyle \large{95-59 = 36}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7B95-59%20%3D%2036%7D)
Therefore, range = 36
Answer:
the answer is a
Step-by-step explanation:
Answer:
0.1527
Step-by-step explanation:
Given that a researcher wishes to conduct a study of the color preferences of new car buyers.
Suppose that 50% of this population prefers the color red
15 buyers are randomly selected
Let X be the no of buyers who prefer red.
X has exactly two outcomes red or non red.
Also each buyer is independent of the other
Hence X is binomial with p = 0.5 and n = 15
Required prob =The probability that exactly three-fifths of the buyers would prefer red
= P(X=9)
= ![15C9 (0.9)^9 (0.6)^6](https://tex.z-dn.net/?f=15C9%20%280.9%29%5E9%20%280.6%29%5E6)
=![5005(0.0000305)=0.1527](https://tex.z-dn.net/?f=5005%280.0000305%29%3D0.1527)