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Lynna [10]
4 years ago
13

Davis predicts that if he spins the spinner another 20

Mathematics
1 answer:
alukav5142 [94]4 years ago
5 0

Answer:

d

Step-by-step explanation:

or if your on online school the last one

No. The frequencies and probabilities for red and green segments might change in the next experiment.

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Marilyn selects a piece of candy at random from a
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Answer: 9/14

Step-by-step explanation: 4+3+2/4+5+3+2 = 9/14

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List the side lengths of XYZ in order from smallest to largest<br><br> _ &lt; _ &lt; _
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Answer:

XZ<ZY<XY

Step-by-step explanation:

smallest angles are across from the smallest sides

I'm not 1000% sure I did this correct??? I hope this was right/it helped though

5 0
3 years ago
12 plus 7 divided by 2 help please
polet [3.4K]

Answer:

15.5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
If A+B= 45° then prove that: tanA+ tanB+ tanA. tanB​
Iteru [2.4K]

Answer:

See Explanation

Step-by-step explanation:

A+B= 45 \degree \\  \\ assuming  \:  \tan \: on \: both \: sides \\  \\\implies \: \tan( A+B)=  \tan 45 \degree \\  \\  \implies \: \tan( A+B)=  1 \:  \: \\  (  \because \: \tan 45 \degree = 1) \\  \\ \implies \:  \frac{\tan \: A +\tan \: B }{1 - \tan \: A .\tan \: B }  = 1 \\  \\ \implies \: \tan \: A +\tan \: B = 1 - \tan \: A .\tan \: B \\  \\ \purple{ \implies }\:  \orange{ \bold{\tan \: A +\tan \: B  + \tan \: A .\tan \: B= 1 }} \\  \\ thus \: proved

8 0
2 years ago
Here are summary statistics for randomly selected weights of newborn​ girls: nequals202​, x overbarequals28.3 ​hg, sequals6.1 hg
Lorico [155]

Answer:

The confidence interval is 27.5 hg less than mu less than 29.1 hg

(A) Yes, because the confidence interval limits are not similar.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = 28.3 hg

sd = 6.1 hg

n = 202

degree of freedom = n-1 = 202-1 = 201

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value corresponding to 201 degrees of freedom and 5% significance level is 1.97196

E = t×sd/√n = 1.97196×6.1/√202 = 0.8 hg

Lower limit = mean - E = 28.3 0.8 = 27.5 hg

Upper limit = mean + E = 28.3 + 0.8 = 29.1 hg

95% confidence interval is (27.5, 29.1)

When mean is 28.3, sd = 6.1 and n = 202, the confidence limits are 27.5 and 29.1 which is different from 27.8 and 29.6 which are the confidence limits when mean is 28.7, sd = 1.8 and n = 17

7 0
4 years ago
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