I believe the answer is TRUE.
When you add them together to get 180 they match.
I hope this helps! :)
<u>Basic answer</u>
When is a quadrilateral a square?
When it has four right angles and four congruent sides.
<u>Geometry Answer (just in case, since the question is vague)</u>
How can you prove if a quadrilateral is a square?
It is a square if it is both a rectangle and a rhombus.
It is a rectangle if
a) It has a right angle and is a parallelogram
b) It has congruent diagonals and is a parallelogram
c) It has four right angles
It is a rhombus if
a) It has two adjacent sides congruent and is a parallelogram
b) Its diagonal bisects opposite angles and it is a parallelogram
c) Its diagonals perpendicular bisect each other
It is a parallelogram if
a) Two pairs of opposite sides parallel
b) Two pairs of opposite sides congruent
c) One pair of sides both congruent and parallel
d) The diagonals bisect each other
e) Two pairs of opposite angles congruent
This is the answer to the problem. You basically substitute the -6 in for the f(x)
Answer:
think it's c
Step-by-step explanation:
two people on each side of the table will be 2 so on 7 table it will be 14 on one side and 14 on the other, that is 28. then you need to add the ends so 2. so now add 28 and 2 and that is 30
She will also need the minimum value, the median, the upper quartile and the lower quartile.
The box will be drawn from the upper quartile to the lower quartile, with a vertical line at the median. The whiskers will go from the box to the highest and lowest values.
