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guapka [62]
2 years ago
12

Marilyn selects a piece of candy at random from a

Mathematics
1 answer:
ki77a [65]2 years ago
3 0

Answer: 9/14

Step-by-step explanation: 4+3+2/4+5+3+2 = 9/14

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Someone please help me!
Nuetrik [128]

Answer:

33

Step-by-step explanation:

25/30=45/x

x=63

63-30=?

?=33

5 0
3 years ago
Find the perimeter of a field that has length 2/x + 1 and width 5/x^2 -1.
Semmy [17]

Answer:

D)4x + 6/(x + 1)(x - 1)

Step-by-step explanation:

A field is basically a rectangle, so to find the perimeter of our field we are using the formula for the perimeter of a rectangle

p=2(l+w)

where

p is the perimeter

l is the length

w is the width

We know from our problem that the field has length 2/x + 1 and width 5/x^2 -1, so l=\frac{2}{x+1} and w=\frac{5}{x^2-1}.

Replacing values:

p=2(l+w)

p=2(\frac{2}{x+1} +\frac{5}{x^2-1})

Notice that the denominator of the second fraction is a difference of squares, so we can factor it using the formula a^2-b^2=(a+b)(a-b) where a is the first term and b is the second term. We can infer that a=x^2 and b=1^2. So, x^2-1=(x+1)(x-1). Replacing that:

p=2(\frac{2}{x+1} +\frac{5}{x^2-1})

p=2(\frac{2}{x+1} +\frac{5}{(x+1)(x-1})

We can see that the common denominator of our fractions is (x+1)(x-1). Now we can simplify our fraction using the common denominator:

p=2(\frac{2(x-1)+5}{(x+1)(x-1)} )

p=2(\frac{2x-2+5}{(x+1)(x-1)} )

p=2(\frac{2x+3}{(x+1)(x-1)} )

p=\frac{4x+6}{(x+1)(x-1)}

We can conclude that the perimeter of the field is D)4x + 6/(x + 1)(x - 1).

3 0
3 years ago
Sarah used her calculator to work out the value of a number y .
mars1129 [50]

Answer:

7.75 \: \leqslant y \:  <  \: 7.85

Step-by-step explanation:

The calculator approximated the value of y at 7.8.

We need to complete the error interval for y.

In other words, we calculate the upper and lower bound for y.

The level level of accuracy is to the nearest tenth.

To find the lower bound, we subtract half the degree of accuracy to get:

y \geqslant 7.8 - 0.05  \\ y  \geqslant 7.75

To find the upper bound, add half the level of accuracy to get:

y \:  <  \: 7.8 + 0.05 \\ y \:  <  \: 7.85

Therefore the error interval is

7.75 \: \leqslant y \:  <  \: 7.85

5 0
3 years ago
Please help answer the question in the picture ​
musickatia [10]
A in the answer for this question
Thank you
3 0
3 years ago
Read 2 more answers
How I solve 11−12y=3+6x for y.
Ganezh [65]

Answer: Y = -x/2+2/3

3 0
4 years ago
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