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3 years ago

Help with math please!!!

Mathematics

1 answer:

romanna [79]3 years ago

7 0

Answer:

Step-by-step explanation: 5 goals were scored every time that exact player was on the ice.

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Can some one help me find x for this equation :<br> (6x^3+11x^2-12x-1)/(3x+1)

Ksenya-84 [330]

The answer is x= -2.5827

7 0

3 years ago

Identify the linear term in the function.<br><br> y = 2x2 − 5x − 12

uranmaximum [27]

Answer:

Step-by-step explanation:

The linear term is always the one with only one x. Always.

-5x has only a single x as a factor.

So - 5x is the linear term.

8 0

3 years ago

Consider the function f(x) = x^3 - 7x^2 - 2x + 14

mars1129 [50]

Answer:

There are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:x^3\:-\:7x^2\:-\:2x\:+\:14$

To get the zeros of $f(x)$ , set $y$ or $f(x) =0$

$0=x^3-7x^2-2x+14$

$x^3\:-\:7x^2\:-\:2x\:+\:14=\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)$

$\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)=0$

Using the zero factor principle:

$\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-7=0\quad \mathrm{or}\quad \:x+\sqrt{2}=0\quad \mathrm{or}\quad \:x-\sqrt{2}=0$

solving

$x-7=0$

$x=7$

$x+\sqrt{2}=0$

$x=-\sqrt{2}$

$x-\sqrt{2}=0$

$x=\sqrt{2}$

Therefore, there are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

8 0

3 years ago

180-8- what is it the answer and how do u sovle it

MatroZZZ [7]

Answer:

172

Step-by-step explanation:

say you have 180 dollars in your hand but you buy some candy that cost 8 dollars. after handing the 8 dollars over your remaining amount would be 172 because you took 8 from the 180 you had.

6 0

3 years ago

Write an algebraic expression to answer each question do this on a sheet of paper

Korolek [52]

Hello.

In 10 years, his age will be

$\mathrm{z+10}$

The sum of his current age and 10 equals his age in 10 years.

2 years ago his age was

$\mathrm{z-2}$

The difference of his current age and 2 equals his age 2 years ago.

7 years ago his age was

$\mathrm{z-7}$

The difference of his current age and 7 equals his age 7 years ago.

Therefore, his age after 10 years will be $\mathrm{z+10}$ , his age 2 years ago was $\mathrm{z-2}$ , and his age 7 years ago was $\mathrm{z-7}$

I hope it helps.

Have a nice day.

$\boxed{imperturbability}$

4 0

2 years ago

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