Answer:
Alfred Hershey and Martha Chase
Explanation:
In 1952 Alfred Hershey and Martha Chase were working with bacteriophages or phages, which are viruses that infect bacteria. They knew that a phage had an outer shell of protein and an inner core of DNA. In addition, from the electron microscope observations, they also knew that during infection the virus attacks the bacterium by its tails and introduces its genetic material into the bacterium to multiply using its metabolic machinery. They radioactively labeled two sets of phages: one with 32P (which marks only DNA) and another with 35S (which marks only proteins). In two parallel experiments, they infected bacteria with viruses marked on their DNA and with viruses marked on their proteins. The cultures were shaken with a mixer to separate the virus particles from the bacterial coatings. They then performed a centrifugation to separate the phages from the bacteria, so that the larger and heavier bacteria remain in the pellet, while the phages remain in the supernatant. They found that the radioactivity of 35S appeared in the supernatant while that of 32P appeared in the sediment, from which new radioactively labeled virus particles appeared, demonstrating that DNA was the genetic material.
The correct option is A. DNA contains genetic codes that code for proteins, which are essential and necessary for the growth and functioning of an organism.
Answer:
The Carbon Cycle
Carbon moves from the atmosphere to plants.
Carbon moves from plants to animals.
Carbon moves from plants and animals to soils.
Carbon moves from living things to the atmosphere.
Carbon moves from fossil fuels to the atmosphere when fuels are burned.
Carbon moves from the atmosphere to the oceans.
Hope This Helps
Answer:
D. the answer is CAT-CGA-TCC mutates to CAT-TC
Explanation:
Answer:
answer is d
Explanation:
THe answer is D because this is dihybrid cross and we cross bwbw RR( normal red eye gene) x RR cncn. The F1 progeny has R in all locus of these genes so all will be R as heterozygous. When F1 progeny crossed, the 1/4 of bw cross and 1/4 of cn cross habe bwbw/cncn and will be white. So it will be 1/4x1/4 = 1/16
