Answer:

Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
![SA=b^{2}+4[\frac{1}{2}bh]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7Dbh%5D)
where
b is the length side of the square base
h is the height of the triangular face
Remember that
Each lateral triangular face is a triangle 45°-90°-45°
so

we have

so

substitute in the formula
![SA=6^{2}+4[\frac{1}{2}(6)(3)]=72\ ft^{2}](https://tex.z-dn.net/?f=SA%3D6%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%286%29%283%29%5D%3D72%5C%20ft%5E%7B2%7D)
B because oil has a lower density than water so oil is on top while water has a higher density and goes down
Answer:
Not enough information
Step-by-step explanation:
You gave the height, but there is no length. You need both the height and length because the area of a triangle is 1/2bh
Yes, they are equivalent
6+7-5=8. -5+10+3=8
Answer:
three times
Step-by-step explanation: