I didn’t really understand number 9

Which is the correct label for the angle?<br> С<br> B

inysia [295]

Did you forget to attach an image?

8 0

3 years ago

Graph the image of the figure using the transformation given. Don't forget prime marks on your new image. Part 1: reflection acr

amm1812

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

J (1, 4 ) → J' (- 1, 4 )

K (1, 0 ) → K' (- 1, 0 )

L (4, 3 ) → L' (- 4, 3 )

Plot the points J', K', L' and connect them in order to obtain image

4 0

3 years ago

Sara and Paul are on opposite sides of a building that a telephone pole fell on. The pole is leaning away from Paul at

r-ruslan [8.4K]

Answer:

a) See figure attached

b) $x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft$

c) $h = 35 sin (59) = 30.0 ft$

So then the heigth for the building is approximately 30 ft

Step-by-step explanation:

Part a

We can see the figure attached is a illustration for the problem on this case.

Part b

For this case we can use the sin law to find the value of r first like this:

$\frac{sin(22)}{35 ft} =\frac{sin(59)}{r}$

$r= \frac{sin(59)}{sin(22)} 35 ft = 80.086ft$

Then we can use the same law in order to find the valueof x liek this:

$\frac{sin(124)}{x ft} =\frac{sin(34)}{80.086}$

$x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft$

And that represent the distance between Sara and Paul.

Part c

For this cas we are interested on the height h on the figure attached. We can use the sine indentity in order to find it.

$sin (59) = \frac{h}{35}$

And if we solve for h we got:

$h = 35 sin (59) = 30.0 ft$

So then the heigth for the building is approximately 30 ft

5 0

3 years ago

A given line has the equation 10x + 2y = −2.

Gekata [30.6K]

Y = -5x + 12 since the slope of that line is -5x and in order to pass through that point the y intercept must be 12

7 0

4 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \

Kisachek [45]

Answer:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2$

Step-by-step explanation:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?$

We can use Part I of the Fundamental Theorem of Calculus:

$\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}$

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

$\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}$

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

$\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

$\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}$

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

$\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

$\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]$
where u represents any function other than a variable

For the first term, replace $\text{t}$ with $2x$ , and apply the chain rule to the function. Do the same for the second term; replace

$\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)$

Simplify the expression by distributing $2$ and $2x$ inside their respective parentheses.

$[-(8x^2 +2)] + (2x^5 + 2x)$
$-8x^2 -2 + 2x^5 + 2x$

Rearrange the terms to be in order from the highest degree to the lowest degree.

$\displaystyle2x^5-8x^2+2x-2$

This is the derivative of the given integral, and thus the solution to the problem.

6 0

3 years ago