find the area of the figure below, composed of a rectangle and semicircle. Round it to the nearest tenth.
1 answer:
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Answer:
Step-by-step explanation:
F(x) = x² - 2x + 1
= (x - 1)²
By comparing this equation with the vertex form of the quadratic equation,
y = (x - h)² + k
Here, (h, k) is the vertex
Vertex of the parabola → (1, 0)
x-intercepts → (x - 1)² = 0
x = 1
y-intercepts → y = (0 - 1)²
y = 1
Now we can draw the graph of the given function,
From this graph,
As x → 0,
f(0) = (0 - 1)²
= 1
Since,
Therefore, given function is continuous at x = 0.
