All categories

3 years ago

A bag contains 13 pieces of candy. In how many ways can five pieces be selected?

Mathematics

1 answer:

Whitepunk [10]3 years ago

3 0

Five pieces can be selected in 1287 ways

Step-by-step explanation:

When the selection has to be made without considering the order of selection, combinations are used.

The formula for combination is:

$C(n,r) = \frac{n!}{r!(n-r)!}$

Here

Total candies = n = 13

Candies to be selected = r = 5

Putting the values in the formula

$C(13,5) = \frac{13!}{5!(13-5)!}\\=\frac{13!}{5!8!}\\=1287\ ways$

Five pieces can be selected in 1287 ways

Keywords: Combinations, selection

Learn more about combinations at:

#LearnwithBrainly

You might be interested in

a) A standard deck consists of 52 cards. Four of the cards are aces. Twenty-six of the cards are red. A poker hand consists of 5

Rzqust [24]

Answer:

a)The number of aces in the poker hand is greater

b)It is about $\sqrt{2}$ as accurate.

5 0

3 years ago

Different sizes of string needs to be cut to go around various shapes. All of the following sizes are in inches.

Brilliant_brown [7]

Answer:

first one

Step-by-step explanation:

6 0

3 years ago

devin used 3 and 3/4 gallons of gas on Saturday and 2 and 7/8 on Sunday. how many gallons of gas did he use on the two days comb

N76 [4]

6 and 5/8 gallons of gas

7 0

3 years ago

Please help me! Solve for x 4−(2x+4)=5

Helga [31]

4−(2x+4)=5
4 - 2x - 4 = 5
-2x = 5
x = -5/2
x = - 2.5

5 0

4 years ago

Read 2 more answers

Lacy draws a diamond from a standard deck of 52 cards. Without replacing the first card, she then proceeds to draw a second card

Viktor [21]

Answer:

a) i) No

ii) Probability of drawing a diamond and then spade without replacement is 0.0637.

b) i) Yes

ii) Probability of drawing a diamond and then spade with replacement is 0.0625

Step-by-step explanation:

Part a) Without replacement:

i) Are these events independent?

No, because the both events are dependent. because a card taken out of the deck is not replaced back before taking out the other card so the chances of event occur change.

ii) Determine the probability of drawing a diamond and then a spade without replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond = 13/52

Probability of drawing a spade:

Total cards in deck after taking diamond = 52 -1 =51

Spades = 13

Probability of drawing a spade = 13/51

Probability of drawing a diamond and then spade = 13/52 * 13/51

= 169/2652

=0.0637

So, Probability of drawing a diamond and then spade without replacement is 0.0637

Part b) With replacements

i) Are these events independent?

Input Yes or No:

Yes, these events are independent because a card taken out of the deck is replaced back before taking out the other card so the chances of event occur doesn't change.

ii) Determine the probability of drawing a diamond and then a spade with replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond = 13/52

Probability of drawing a spade:

Total cards in deck after replacing diamond = 52

Spades = 13

Probability of drawing a spade = 13/52

Probability of drawing a diamond and then spade = 13/52 * 13/52

= 169/2704

=0.0625

So, Probability of drawing a diamond and then spade with replacement is 0.0625

7 0

4 years ago