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3 years ago

A bag contains 13 pieces of candy. In how many ways can five pieces be selected?

Mathematics

1 answer:

Whitepunk [10]3 years ago

3 0

Five pieces can be selected in 1287 ways

Step-by-step explanation:

When the selection has to be made without considering the order of selection, combinations are used.

The formula for combination is:

$C(n,r) = \frac{n!}{r!(n-r)!}$

Here

Total candies = n = 13

Candies to be selected = r = 5

Putting the values in the formula

$C(13,5) = \frac{13!}{5!(13-5)!}\\=\frac{13!}{5!8!}\\=1287\ ways$

Five pieces can be selected in 1287 ways

Keywords: Combinations, selection

Learn more about combinations at:

#LearnwithBrainly

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Art [367]

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Sam will make 8 cuts as stated in the question.

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3 years ago

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4 years ago

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3 years ago

I don't even know how to figure this out. I don't have a formula for this

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Answer:

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4 years ago

If aſc and a +b = C, prove that a|b.

mars1129 [50]

Answer with Step-by-step explanation:

Since we have given that

a + b = c

and a|c

i.e. a divides c.

We need to prove that a|b.

⇒ a = mb for some integer m

Since a|c,

So, mathematically, it is expressed as

c= ka

Now, we put the above value in a + b = c.

So, it becomes,

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a=mb, here, m = k-1

Hence, proved.

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3 years ago