2 years ago

Two or more basic geometic figures may be combined to form what

1 answer:

3 0

The correct answer to the question that is being asked and presented above would be 'composite'. If there are two or more basic geometric figures combined, they form what is called a 'composite' figure.

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The circle given by x^2+y^2-6y-12=0 can be written in standard form like this: x^2+(y-k)^2=21 What is the value of k in this equ

sweet [91]

Answer:

The value of k =3

Step-by-step explanation:

$x^2+y^2-6y-12=0$ We need to solve this equation to become in standard form to find the value of k.

$x^2+y^2-6y-12=0\\x^2+y^2-6y = 12\\(x)^2 +(y^2-2(y)(3)+(3)^2) = 12 +(3)^2\\(x)^2+(y-3)^2 = 12+9\\(x)^2 +(y-3)^2 = 21$

The given standard form is:

$x^2+(y-k)^2=21$

Comparing it with $(x)^2 +(y-3)^2 = 21$

The value of k =3

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2 years ago

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How would I find the area given these 4 points? Is there a formula that I just don't know

Dmitrij [34]

Answer: No

Step-by-step explanation:

I can’t think of one but if you have a pegboard there is a formula called Pick’s Formula

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3 years ago

The volume of a? cone-shaped hole is 49 pi ft cubed . If the hole is 3 ft? deep, what is the radius of the? hole?

lidiya [134]

$\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ h=3\\ V=49\pi \end{cases}\implies 49\pi =\cfrac{\pi r^2(3)}{3}\implies 49\pi =\pi r^2 \\\\\\ \cfrac{49\pi }{\pi }=r^2\implies 49=r^2\implies \sqrt{49}=r\implies 7=r$