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3 years ago

13

Two or more basic geometic figures may be combined to form what

1 answer:

Katyanochek1 [597]3 years ago

3 0

The correct answer to the question that is being asked and presented above would be 'composite'. If there are two or more basic geometric figures combined, they form what is called a 'composite' figure.

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a spinner is divided into eight equal parts numbered 1 to 8. if the spinner is spun once, what is the probability that it stops

Step2247 [10]

Since the total number of available selections is divided by two, the probability is 50%. If we look at the total set of numbers, we find that even numbers are multiples of 2. 2, 4, 6, 8 (which makes up half of the numbers on the spinner).

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3 years ago

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In the diagram, ABC is a straight line such that AB = 6.8 cm,BC=17.6cm,BD=8.8

grandymaker [24]

Answer: a.= 28.2°, b= 13.6cm, c = 3.2cm.

Step-by-step explanation:

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3 years ago

Can i get some help and a good explenation

denis-greek [22]

Answer:

The correct answer is $2,50

Step-by-step explanation:

The unit rate is what we use to determine the price of a single unit, when something is sold in a group, as in this case 5 ounces.

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3 years ago

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When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected

jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

$N=\frac{12.36}{0.03+0.55^t}$

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

$N=\frac{12.36}{0.33+0.55^0}$

$N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12$

A. Initially, there were 12 deer.

B. $N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380$

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. $N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410$

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

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3 years ago

Last year, 75 new houses were built in a neighborhood. So far this year, 4/5 of them have been sold. How many new houses have be

valina [46]

Answer:

60 sold

Step-by-step explanation:

4/5 of 75 new houses sold this year comes out to 60 new houses sold. Just multiply the total (75 houses) by this fraction (4/5).

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3 years ago

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