Answer:
Step-by-step explanation:
Given that Rafaela is a physical education teacher and has 25 girls and 35 boys in her class.
She wants to divide the class into teams of the same size, where each team has the same number of girls and the same number of boys. If Rafaela creates the greatest number of teams possible, how many boys will be on each team?
Here we find Highest common factor for 25 and 35 and it is 5
So 5 boys will be on each team (with 7 girls)
2) length I = 7m, x12 m and height = 3mx85 cm.
The longest tape would be the highest common factor of 12 and 85
Since it is 1, only 1 cm long tape can be used.
Given:
The inequality is

To find:
The solution of the given inequality.
Solution:
We have,

Isolate the variables terms on the left side.


Divide both sides by -5 and change the inequality sign as we divide the equality by a negative value.


Therefore, the correct option is D.
No, they are not equivalent. The numerators are equals, but the denominators are not, they are not equivalent. If the first one would be 6/8, they would be equivalent, because we can simplify the fractions by 2 and we got 3/4 again. Good luck !
Answer:
The 90% confidence interval would be given by (0.026;0.073)
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The population proportion have the following distribution
Solution to the problem
The estimated proportion for this case is:

Represent the proportion of defectives for this case
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by
and
. And the critical value would be given by:
The confidence interval for the mean is given by the following formula:
If we replace the values obtained we got:
The 90% confidence interval would be given by (0.026;0.073)