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Lesechka [4]
3 years ago
7

How do you factor this problem? I know you have to pull out the GCF first but I'm still stumped. 18x³-51x²+36x​

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0

Answer:

one is direct x = 0 , next we need to find out 18x^2 - 51x + 36. ( Shri Dharacharya formula)

Step-by-step explanation:

1. ( - (-51) + - √ ( 51^2 - 4* 18 *36)) / 2* 18

2. ( 51 + - 3 ) / 36

3. x = 0 , x = 3/2 , x = 4/3

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Rafaela is a physical education teacher and has 25 girls and 35 boys in her class. She wants to divide the class into teams of t
Phantasy [73]

Answer:

Step-by-step explanation:

Given that Rafaela is a physical education teacher and has 25 girls and 35 boys in her class.

She wants to divide the class into teams of the same size, where each team has the same number of girls and the same number of boys. If Rafaela creates the greatest number of teams possible, how many boys will be on each team?

Here we find Highest common factor for 25 and 35 and it is 5

So 5 boys will be on each team (with 7 girls)

2) length I = 7m, x12 m and height = 3mx85 cm.

The longest tape would be the highest common factor of 12 and 85

Since it is 1, only 1 cm long tape can be used.

7 0
3 years ago
-2x+2&gt;3x-8<br><br> 50 points
Blababa [14]

Given:

The inequality is

-2x+2>3x-8

To find:

The solution of the given inequality.

Solution:

We have,

-2x+2>3x-8

Isolate the variables terms on the left side.

-2x-3x>-2-8

-5x>-10

Divide both sides by -5 and change the inequality sign as we divide the equality by a negative value.

\dfrac{-5x}{-5}

x

Therefore, the correct option is D.

5 0
3 years ago
Find the sum of the first 63 terms of –19, -13, -7 …
Degger [83]

You can tell this is an arithmetic sequence because it is a list of terms beginning with -19 that increase by 6 each term. Because of this, we can use the formula for the sum of an arithmetic sequence, which is:

S = \dfrac{n}{2}[2 a_1 + d(n - 1)]

  • n is the number of terms in the sequence
  • a_1 is the starting term
  • d is the common difference among the terms

In this case, we can see that n = 63, a_1 = -19, and d = 6. Thus, we can use the formula:

S = \dfrac{63}{2} [2(-19) + 6(62)] = 10,521


Our answer is 10,521.


7 0
3 years ago
Is 3/4 and 3/8 equivalent fractions and why? Thanks
uranmaximum [27]
No, they are not equivalent. The numerators are equals, but the denominators are not, they are not equivalent. If the first one would be 6/8, they would be equivalent, because we can simplify the fractions by 2 and we got 3/4 again. Good luck !
4 0
3 years ago
Read 2 more answers
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :
stiks02 [169]

Answer:

0.0497 - 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.026

0.0497 + 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.073

The 90% confidence interval would be given by (0.026;0.073)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The estimated proportion for this case is:

\hat p =\frac{322-306}{322}= 0.0497

Represent the proportion of defectives for this case

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.0497 - 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.026

0.0497 + 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.073

The 90% confidence interval would be given by (0.026;0.073)

3 0
3 years ago
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