To solve the problem, we can first change the denominator into the same:
3 1/3 - 1 2/9
= 3 (1×3)/(3×3) - 1 2/9
= 3 3/9 - 1 2/9
We can then proceed to carry deduction:
3 3/9 - 1 2/9
= 2 1/9
Therefore the answer is 2 1/9.
Answer:
X Y and Z are the variables.
Step-by-step explanation
Part A:
Significant level:
<span>α = 0.05
Null and alternative hypothesis:
</span><span>h0 : μ = 3 vs h1: μ ≠ 3
Test statistics:
P-value:
P(-0.9467) = 0.1719
Since the test is a two-tailed test, p-value = 2(0.1719) = 0.3438
Conclusion:
Since the p-value is greater than the significant level, we fail to reject the null hypothesis and conclude that there is no sufficient evidence that the true mean is different from 3.
Part B:
The power of the test is given by:
Therefore, the power of the test if </span><span>μ = 3.25 is 0.8105.
Part C:
</span>The <span>sample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is obtained as follows:
Therefore, the </span>s<span>ample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is 16.</span>
2.5*d+5= 65
subtract 65 by 5 and divide by 2.5 to get the number of days shes had the plant :)
Answer:
-234
Step-by-step explanation:
5x + 4y =8 2x -3y = 17 -3 O -2 O 4 O5=234