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3 years ago

What is the total surface area of the square pyramid in square inches

Mathematics

1 answer:

sladkih [1.3K]3 years ago

8 0

7x9=63
63÷2= 31.5x4
126= area of the triangles

7x7= 49= area of the square.

126+49= 175 ft

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How would you turn 7/18 into a decimel and round to the nearest hundreths

Tema [17]

It would be 0.38 the 8 is repeating

6 0

2 years ago

Lashonda is saving money to buy a game. So far she has saved $6, which is two-thirds of the total cost of the game. How much doe

aliina [53]

Answer:

The game costs $9

Step-by-step explanation:

I wrote an equation using the variable "t" for the total cost of the game.

6=2/3t

t=6/2/3

t=(6/1)(3/2)

t=18/2

t=9

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2 years ago

What is the smallest positive integer that Anastasia could have thought of?

Dima020 [189]

Answer:

Step-by-step explanation:

an integer is a natural counting number, such as 1...2...3...4... and so on....

zero is not considered an integer because it is a neutral number.

therefore, the smallest possible positive integer would have to be 1!

i hope this helped you!

stay safe!

3 0

2 years ago

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

2 years ago

-29 19/40 as a decimal

Mariulka [41]

19 divided by 40 is .475 so it’s -29.475

7 0

2 years ago