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2 years ago

5√-54 in simplest radical form

Mathematics

2 answers:

olga nikolaevna [1]2 years ago

3 0

The answer is 15i radical 6

sergey [27]2 years ago

3 0

-2.99999999998 math is fun sometimes

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NEED HELP ASAP WITH THIS QUESTION

Elis [28]

Answer:

ITS c

Step-by-step explanation:

trust me bestie

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2 years ago

I need help on this one plzz

masya89 [10]

I’m pretty sure the answer is C

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2 years ago

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A rectangular piece of land borders a wall. The land is to be enclosed and to be into divided 3 equal plots with 200 feet of fen

baherus [9]

Answer:

Area = 2500 square feet is the largest area enclosed

Step-by-step explanation:

A rectangular piece of land borders a wall. The land is to be enclosed and to be into divided 3 equal plots with 200 feet of fencing

Let x be the length of each box and y be the width of the box

Perimeter of the box= 3(length ) + 4(width)

$200=3x+4y$

solve for y

$200=3x+4y$

$200-3x=4y$

divide both sides by 4

$y=50-\frac{3x}{4}$

Area of the rectangle = length times width

$Area = 3x \cdot y$

$Area = 3x \cdot (50-\frac{3x}{4})$

$A=150x-\frac{9x^2}{4}$

Now take derivative

$A'=150-\frac{9x}{2}$

Set it =0 and solve for x

$0=150-\frac{9x}{2}$

$150=\frac{9x}{2}$

multiply both sides by 2/9

$x=\frac{100}{3}$

$A''=-\frac{9}{2}$

For any value of x, second derivative is negative

So maximum at x= 100/3

$A=150x-\frac{9x^2}{4}$ , replace the value of x

$A=150(\frac{100}{3})-\frac{9(\frac{100}{3})^2}{4})$

Area = 2500 square feet is the largest area enclosed

3 0

2 years ago

What is the area of a triangular yield sign whose base is 16 inches and height is 12 inches? Write only the number rounded to th

Tems11 [23]

Check the picture below

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3 years ago

There are 10 kids on the math team. Two kids will be selected from the team to compete in the state competition. How many ways a

patriot [66]

Answer:

45 ways

Step-by-step explanation:

Total number of kids = 10

We have to select the 2 kids

So the number ways to select two kids $^{10}C_2$

We know that $^{n}C_r=\frac{n!}{r!(n-r)!}$

So $^{10}C_2=\frac{10!}{2!(10-2)!}=\frac{10!}{2!\times 8!}=\frac{10\times 9\times 8!}{2\times 8!}=45$

So there are 45 ways to select 2 competitors

8 0

3 years ago