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Dvinal [7]
3 years ago
13

Complex roots problem

Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

b^2-4ac >0  the roots are real

Step-by-step explanation:

b^2-4ac >0  the roots are real

b^2-4ac = 0 there is 1 root

b^2 -4ac <0 the root are complex

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8 0
3 years ago
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Use linear regression to find a
Inessa [10]

A function that fits the following points (0,5), (2,-13) is y = 9x + 5

<h3>Equation of a line</h3>

The equation of a line in slope-intercept form is expressed as;

y =mx +b

where;

m is the slope

b is the intercept

Given the following coordinates (0,5), (2,-13)

Slope = -13-5/2-0
Slope = -18/-2

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Since the y-intercept is b = 5, hence the equation of the line will be y = 9x + 5

Learn more on linear regression here; brainly.com/question/25987747

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6 0
2 years ago
HELP ME WITH MATHHHHH ILL GIVE YOU BRAINLIEST
Alla [95]

Answer:

  -3, 1, 4 are the x-intercepts

Step-by-step explanation:

The remainder theorem tells you that dividing a polynomial f(x) by (x-a) will result in a remainder that is the value of f(a). That remainder will be zero when (x-a) is a factor of f(x).

In terms of finding x-intercepts, this means we can reduce the degree of the polynomial by factoring out the factor (x-a) we found when we find a value of "a" that makes f(a) = 0.

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For the given polynomial, we notice that the sum of the coefficients is zero:

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Using synthetic division to find the quotient (and remainder) from division by (x-1), we see that ...

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  f(x) = (x -1)(x -4)(x +3)

Synthetic division confirms that the remainder from division by (x -4) is zero, so x=4 is another x-intercept. The result of the synthetic division confirms that x=-3 is the remaining x-intercept.

The x-intercepts of f(x) are -3, 1, 4. These are the points you want to plot on your number line.

5 0
2 years ago
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Gennadij [26K]

Answer:

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Answer:

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3 years ago
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