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Dvinal [7]
3 years ago
13

Complex roots problem

Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

b^2-4ac >0  the roots are real

Step-by-step explanation:

b^2-4ac >0  the roots are real

b^2-4ac = 0 there is 1 root

b^2 -4ac <0 the root are complex

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3x-6y. you need to take away the parentheses and combine like terms

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Think about the sets of rational numbers, integers, and whole numbers.
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3 years ago
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$35,000 at 2% for 9 years. ending balance and interest
love history [14]

Answer:

Solution

Here,

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6 0
2 years ago
Would you please help me solve for x it should be a degrees but I’m not sure what it is
Leno4ka [110]

Answer:

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Step-by-step explanation:

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Since ∠C does not have an angle, knowing that a straight line is 180º we can subtract it from 45º to find ∠C.

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6 0
2 years ago
(2x-1) (4x+1) solve equation
ElenaW [278]
(2x-1)(4x+1) just multiply the terms in the parentesis

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You get:

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Final result:

8x^2-2x-1
8 0
3 years ago
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