Solve the equation r²-4s+s²=8r+2s=28

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

5 0

Answer:

${r}^{2} - 4s + {s}^{2} = 8r + 2s = 28 \\ \\ r = \frac{24}{5 } - i \frac{ \sqrt[4]{129} }{5} \\ \: s = \frac{58}{5} + i \frac{ \sqrt[2]{129} }{5 } \\ \\ r = \frac{24}{5} + i \frac{ \sqrt[4]{129} }{5} \\ s = \frac{58}{5} - i \frac{ \sqrt[2]{129} }{5}$

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Can someone please help me?

Alisiya [41]

Answer:

Step-by-step explanation:

That composite figure is made up of a square and a quarter of a circle. We will first find the area of the square. Then we will find the area of the circle and divide it by 4.

Area of square = 1.6 × 1.6

Area of square = 2.56 m squared

Area of circle = (3.14)(1.6²) In case you forgot, the area of a circle is A = πr².

Area of circle = 8.0384

Divide that by 4 to get 2.0096.

Add 2.0096 to 2.56 to get the total area, which is

4.5696 or 4.6 rounded (choice D)

8 0

3 years ago

help pls! will give brainliest to whoever answers correctly and explains their answer. (PLS DONT ANSWER IF YOU DONT KNOW)

Aleks [24]

Answer:

the answer is C. how you got 24

Step-by-step explanation:

so find the square of 2 first and that would give -8

-8*4 is -32

8 0

3 years ago

Read 2 more answers

Which is true about the completely simplified difference of the polynomials a3b 9a2b2 − 4ab5 and a3b − 3a2b2 ab5?.

PtichkaEL [24]

The simplified difference of the polynomials (a³b+9a²b²-4ab⁵) and (a³b-3a²b²+ab⁵) is (12a²b²-5ab⁵).

<h3>What are Like terms?</h3>

Like terms are those terms that are having the same variables, also the variables are of the same order as well.

for example, 25x and 5x are like terms; 30xy and 7xy are like terms, 9x³ and 4x² are not like terms, etc.

Let's simplify the two of the given polynomials, therefore, find the difference between the two given polynomials.

$a^3b+9a^2b^2 - 4ab^5 - (a^3b - 3a^2b^2+ab^5)\\\\= a^3b+9a^2b^2 - 4ab^5 - a^3b + 3a^2b^2-ab^5\\\\\text{Bring Like terms together}\\\\=a^3b - a^3b+9a^2b^2+3a^2b^2 -4ab^5-ab^5\\\\= 12a^2b^2-5ab^5$