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Maksim231197 [3]
3 years ago
6

How do you find the general solution for cos2A=cos^2A

Mathematics
1 answer:
eduard3 years ago
6 0

Answer:

A =  0 +/- nπ radians ,  where n is an integer.

Step-by-step explanation:

cos 2A =  cos^2 A

Use the identity cos 2A = 2 cos^2 A -1  :

2cos^2 A - 1 = cos^2 A

cos^2 A = 1

Cos A = +/-1

When cos A = 1,  A = 0 +/- 2nπ radians.

when cos A = -1, A = π +/- nπ radians.

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Answer:

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f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

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A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

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