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Inga [223]
3 years ago
5

Solve the equation 3/7k=12/35

Mathematics
1 answer:
zepelin [54]3 years ago
6 0
3/7k=12/35 is the answer to this question

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Morgan wants to sell his bike and does research online to determine what his selling price should be. He finds $25$ bikes of the
Setler79 [48]

p= 750y

(thats the best i can do i learned this a long time ago like in 4th grade so i kinda forgot sorry!!!)

8 0
3 years ago
If the ratio of the areas of two similar polygons is 32:50, what is the ratio of the corresponding side lengths?
Nonamiya [84]

Answer:

64;100

Step-by-step explanation:

5 0
3 years ago
which represents the solution(s) of the system of equations, y=x^2-2x-15 and y=8x-40? determine the solution set algebraically
Harrizon [31]
y=x^2-2x-15 (1) y=8x-40 (2)

8x-40=x^2-2x-15
X^2+10x-25=0
(x-5)^2
×=5 y=0
7 0
3 years ago
F(x) =2x-5 and g(x) =x+52 find f(g(x)
irga5000 [103]
If f(x) = 2x - 5 and g(x) = x + 52, then f(g(x)) can be deduced by placing g(x) in the spot of x in the f(x) equation as follows:

f(g(x)) = 2(g(x)) - 5

Since we know g(x) = x + 52, let's plug it in:

f(g(x)) = 2(x + 52) - 5
f(g(x)) = 2x + 104 - 5
f(g(x)) = 2x + 99
4 0
3 years ago
Read 2 more answers
Geometric sequences HELP ASAP!
Pani-rosa [81]

Given:

The table for a geometric sequence.

To find:

The formula for the given sequence and the 10th term of the sequence.

Solution:

In the given geometric sequence, the first term is 1120 and the common ratio is:

r=\dfrac{a_2}{a_1}

r=\dfrac{560}{1120}

r=0.5

The nth term of a geometric sequence is:

a_n=ar^{n-1}

Where a is the first term and r is the common ratio.

Putting a=1120, r=0.5, we get

a_n=1120(0.5)^{n-1}

Therefore, the required formula for the given sequence is a_n=1120(0.5)^{n-1}.

We need to find the 10th term of the given sequence. So, substituting n=10 in the above formula.

a_{10}=1120(0.5)^{10-1}

a_{10}=1120(0.5)^{9}

a_{10}=1120(0.001953125)

a_{10}=2.1875

Therefore, the 10th term of the given sequence is 2.1875.

6 0
3 years ago
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