Solve the equation 3/7k=12/35

Mathematics

1 answer:

zepelin [54]4 years ago

6 0

3/7k=12/35 is the answer to this question

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5) A cube has height of 3 cm. What is the volume of the cube?

ElenaW [278]

Answer:

V =27cm^3

Step-by-step explanation:

The volume of a cube is given by

V = s^3 where s is the side length

V = 3^3

V =27cm^3

6 0

3 years ago

Read 2 more answers

Please help answer alll

poizon [28]

A= there are "4"one fourths in one hour and he hikes 2 miles every hour

B= 1, 1 1/2, 2, 4

C= it going to be 1/3 mile for every 1/6hour and she hikes 2 miles every hour.

D= 2/3, 1, 2, 4

7 0

3 years ago

The weight of a radioactive isotope was 96 grams at the start of an experiment. After one hour, the weight of the isotope was ha

zimovet [89]

The starting weight of the radioactive isotope = 96 grams

Weight after one hour is half of the starting weight. So the weight of the radioactive isotope after 1 hour = 48 grams

After 2 hours the weight is half as compared to the weight after previous hour. So weight after 2 hours = 24 grams.

This means, after every hour the weight is being halved. The half life of radioactive isotope is one hour.

Since after every hour, the weight is being halved, the weight of the isotope can be modeled by an exponential equation.

So,

Initial Weight = W₁ = 96
Change factor = 1/2 = 0.5

The general equation of the sequence will be:

$\\ \\ W_{t}=96(0.5)^{t}$

Here t represents the number of hours. Using various values of t we can find the weight of the radioactive isotope at that time.

We can plot the sequence using the above equation. The graph is attached below.