To find the cost of one, divide 10.38 by 6, so
10.38/6 = 1.73
1.73 = price per battery
To find the price of 8, multiply the cost of price per battery with however many items you need, in this case 8 so,
1.73 x 8 = 13.84
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
The answer for this proportion is 50.
156.25 times 16 =2,500
2,500 divided by 50=50
X=50
Your correct answer is c.
Answer:
B
Step-by-step explanation:
The differences in the terms of f(x) are + 3, + 5, + 7
Since the differences are not constant the relationship is not linear
Note the differences in the differences are + 2, + 2,
The second differences are constant indicating a quadratic relationship
Note the relationship between x and f(x)
x = 1 → 1² = 1 ← require to add 5, that is 1 + 5 = 6 ← value of f(x)
x = 2 → 2² = 4 ← require to add 5, that is 4 + 5 = 9 ← value of f(x)
x = 3 → 3² = 9 ← require to add 5, that is 9 + 5 = 14 ← value of f(x)
x = 4 → 4² = 16 ← require to add 5, that is 16 + 5 = 21 ← value of f(x)
Thus f(x) = x² + 5 → B
