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3 years ago

Need urgent help in mathematics!! Will mark brainliest!!!! PLEASE look at the photo to answer the question .....

Mathematics

1 answer:

Mila [183]3 years ago

3 0

Don’t let the letter scare you, imagine this as a simple cross product!

(32 × 1) ÷ 8 = m

32 ÷ 8 = m

4 = m

There you go, the solution to this equation is that m = 4!

I really hope this helped, if there’s anything just let me know! ☻

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Angelo rode his bike around a bike trail that was 1/4 of a mile long. He rode his bike around the trail 8 times. Angelo says he

bulgar [2K]

Teresa is correct because he rode a 1/4 mile bike trail 8 times and if you simplify 8/4 miles it would be 2 miles

7 0

3 years ago

Two of the exterior angles of a triangle are $158^\circ$ and $99^\circ.$ Find the third exterior angle, in degrees.

Lisa [10]

Answer:

The third exterior angle is $103^o$

Step-by-step explanation:

Given

$\theta = 158^o$

$\alpha = 99^o$

Required

The third exterior angle $(\beta)$

The exterior angles of a triangle add up to 360 degrees.

So:

$\theta + \alpha + \beta = 360^o$

Make $\beta$ the subject

$\beta = 360^o - (\theta + \alpha)$

Substitute known values

$\beta = 360^o - (158^o + 99^o)$

$\beta = 103^o$

4 0

3 years ago

I need to find the value of x with the given information

Vika [28.1K]

Answer:

BD is half of the answer BF is

Step-by-step explanation:

BD is only half of BF so find the answer for BF and then divide by @ and you have your answer.

6 0

2 years ago

A tank has capacity 6 L and initially contains 11 mg of salt dissolved in 3 L of water. A solution containing 1 mg/L of salt ent

BlackZzzverrR [31]

Answer:

The answer is below

Step-by-step explanation:

a) The maximum capacity of he tank is 6 L and initially it contains 11 mg of salt dissolved in 3 L of water. Solution enters the tank at a rate of 3 L/hr, therefore in x hours, the amount of water that have entered the tank = 3x.

Solution also leaves the tank at a rate of 2L/hr, therefore in x hours, the amount of water that have left the tank = 2x

Hence the amount of water present in the tank at x hours is given as:

3 + 3x - 2x = 3 + x

The time taken to full the tank can be gotten from:

3 + x = 6

x = 6 - 3

x = 3 hr

$\frac{dQ}{dx}=3-\frac{2Q}{3+x}\\ \\\frac{dQ}{dx}+\frac{2Q}{3+x}=3\\\\let\ u'=\frac{2u}{3+x}\\\\\frac{u'}{u}=\frac{2Q}{3+x}\\\\ln(u)=2ln(3+x)\\\\u=(3+x)^2\\\\(3+x)^2Q]'=3(3+x)^2\\\\(3+x)^2Q=(3+x)^3+c\\\\Q(0)=11\\\\(3+0)^2(11)=(3+0)^3+c\\\\x=72\\\\Q=x+3+\frac{72}{(x+3)^2}\\ \\Q(3)=3+3+\frac{72}{(3+3)^2}=8\ mg$

8 mg/ 6 L = 4/3 mg/L

8 0

3 years ago

G(t)=(t+1) ^2-20.25 what are the zeros of the function

Vinil7 [7]

Step-by-step explanation:

g(t) = (t + 1)² − 20.25

0 = (t + 1)² − 20.25

20.25 = (t + 1)²

±4.5 = t + 1

t = -1 ± 4.5

t = -5.5 or 3.5

The zeros are (-5.5, 0) and (3.5, 0).

5 0

3 years ago