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3 years ago

Need urgent help in mathematics!! Will mark brainliest!!!! PLEASE look at the photo to answer the question .....

Mathematics

1 answer:

Mila [183]3 years ago

3 0

Don’t let the letter scare you, imagine this as a simple cross product!

(32 × 1) ÷ 8 = m

32 ÷ 8 = m

4 = m

There you go, the solution to this equation is that m = 4!

I really hope this helped, if there’s anything just let me know! ☻

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A line passes through point A (14,21). A second point on the line has an x-value that is 125% of the x-value of point A and a y-

seropon [69]

Answer:

The equation of the line in point-slope form is $y-21 = - \frac{3}{2}\cdot (x-14)$ .

Step-by-step explanation:

According to the statement, let $A(x,y) = (14,21)$ and $B(x,y) = (1.25\cdot x_{A},0.75\cdot y_{A})$ . The equation of the line in point-slope form is defined by the following formula:

$y-y_{A} = m\cdot (x-x_{A})$ (1)

Where:

$x_{A}$ , $y_{A}$ - Coordinates of the point A, dimensionless.

$m$ - Slope, dimensionless.

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

In addition, the slope of the line is defined by:

$m = \frac{y_{B}-y_{A}}{x_{B}-x_{A}}$ (2)

If we know that $x_{A} = 14$ and $y_{A} = 21$ , then the equation of the line in point-slope form is:

$x_{B} = 1.25\cdot (14)$

$x_{B} = 17.5$

$y_{B} = 0.75\cdot (21)$

$y_{B} = 15.75$

From (2):

$m = \frac{15.75-21}{17.5-14}$

$m = -\frac{3}{2}$

By (1):

$y-21 = - \frac{3}{2}\cdot (x-14)$

The equation of the line in point-slope form is $y-21 = - \frac{3}{2}\cdot (x-14)$ .

5 0

3 years ago

Ratios, decimals, simplest form

Aleks04 [339]

101 to 263, 101 / 263,

8 0

3 years ago

PLEASE HELP HURRY<br><br> Thanks!!!!!!<br><br> This is math :)

PIT_PIT [208]

Answer:

DON'T PRES THAT LINK THAT IS A HACK AND VIRUS

Step-by-step explanation:

HOPE THIS LETS YOU REMEMBER ABOUT NOT PRESSING THESE LINKS!

4 0

3 years ago

(4.1.4) Let X and Y be Bernoulli random variables. Let Z = X + Y. a. Show that if X and Y cannot both be equal to 1, then Z is a

Fynjy0 [20]

Step-by-step explanation:

Given that,

X ~ Bernoulli $(p_x)$ and Y ~ Bernoulli $(y_x)$

X + Y = Z

The possible value for Z are Z = 0 when X = 0 and Y = 0

and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0

If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,

Therefore Z is a Bernoulli random variable

If X and Y can not be both equal to 1

then,

$p_z = P(X=1$ or $Y=1)\\$

$p_z = P(X=1)+P(Y=1)-P(=1$ and $Y =1)$

$p_z = P(x=1)+P(Y=1)\\\\p_z=p_x+p_y$

If both X = 1 and Y = 1 then Z = 2

The possible values of the random variable Z are 0, 1 and 2.

since a Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution

7 0

3 years ago

……………..??????????????

padilas [110]

That’s a tricky stem and leaf plot, Anw as the key shows 11|6 =16

So the most common arm span is 12 the least commons are 11,17,19,22 which appear only one time. So I’d say there are no outliers

8 0

2 years ago