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borishaifa [10]
3 years ago
5

Ginger, Inc., has declared a $5.40 per share dividend. Suppose capital gains are not taxed, but dividends are taxed at 20 percen

t. New IRS regulations require that taxes be withheld at the time the dividend is paid. The company's stock sells for $94.00 per share, and the stock is about to go ex dividend. What do you think the ex-dividend price will be
Business
1 answer:
lesantik [10]3 years ago
4 0

Answer: $89.68

Explanation:

The Ex-dividend measures how much a stock price drops as a result of the disbursement of dividends. It is calculated by subtracting the dividend from the current stock price.

In the above question the IRS require that taxes be withheld at the time that the dividend is paid.

This means that taxes have to be accounted for first before ex - dividend is calculated.

After tax dividend = 5.40 * ( 1 - 0.2)

After tax dividend = $4.32

Solving for Ex-dividend gives,

= 94.00 - 4.32

= $89.68

The ex-dividend price will be $89.68

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a) $y=0.00991 x+1.042$b) $r^2=0.7503^2=0.563$\\C) $r=\frac{7(30095)-(4210)(49)}{\sqrt{\left[7(2595100)-(4210)^2\right]\left[7(354)-(49)^2\right]}}=0.7503$

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We want to create a linear model like this :

$$y=m x+b$$

Where

$$m=\frac{S_{x y}}{S_{x x}}$$

And:  

$$\begin{aligned}& S_{x y}=\sum_{i=1}^n x_i y_i-\frac{\left(\sum_{i=1}^n x_i\right)\left(\sum_{i=1}^n y_i\right)}{n} \\& S_{x x}=\sum_{i=1}^n x_i^2-\frac{\left(\sum_{i=1}^n x_i\right)^2}{n}\end{aligned}$$

With these we can find the sums:  

$$\begin{aligned}& S_{x x}=\sum_{i=1}^n x_i^2-\frac{\left(\sum_{i=1}^n x_i\right)^2}{n}=2595100-\frac{4210^2}{7}=63085.714 \\& S_{x y}=\sum_{i=1}^n x_i y_i-\frac{\left(\sum_{i=1}^n x_i\right)\left(\sum_{i=1}^n y_i\right) n}{=} 30095-\frac{4210 * 49}{7}=625\end{aligned}$$

And the slope would be:  

m=\frac{625}{63085.714}=0.00991

Now we can find the means for x and y like this:

$$\begin{aligned}& \bar{x}=\frac{\sum x_i}{n}=\frac{4210}{7}=601.429 \\& \bar{y}=\frac{\sum y_i}{n}=\frac{49}{7}=7\end{aligned}$$

And we can find the intercept using this:

$$b=\bar{y}-m \bar{x}=7-(0.00991 * 601.429)=1.042$$

And the line would be:

$$y=0.00991 x+1.042$$

Part b

The correlation coefficient is given by:

r=\frac{n\left(\sum x y\right)-\left(\sum x\right)\left(\sum y\right)}{\sqrt{\left[n \sum x^2-\left(\sum x\right)^2\right]\left[n \sum y^2-\left(\sum y\right)^2\right]}}

For our case we have this:

$$\begin{aligned}& \mathrm{n}=7 \sum x=4210, \sum y=49, \sum x y=30095, \sum x^2=2595100, \sum y^2=354 \\& r=\frac{7(30095)-(4210)(49)}{\sqrt{\left[7(2595100)-(4210)^2\right]\left[7(354)-(49)^2\right]}}=0.7503\end{aligned}$$

The determination coefficient is given by:

$$r^2=0.7503^2=0.563$$

Part c

r=\frac{7(30095)-(4210)(49)}{\sqrt{\left[7(2595100)-(4210)^2\right]\left[7(354)-(49)^2\right]}}=0.7503

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