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2 years ago

14

X+4 divided by x^2+16 Why can't it be simplified?

1 answer:

KonstantinChe [14]2 years ago

8 0

Let's try to simplify x^2 + 16. It's a sum of two squares:

x^2 + 16 = 0

x^2 = -16

The problem is, we can't take a square root of a negative. This is where imaginary numbers come in.

Remember that square roots have a plus or minus symbol outside:

±√-16 = ±4i

Our two roots are 4i and -4i. Therefore, the trinomial simplifies to:

(x + 4i)(x - 4i)

If we attempt to divide x + 4 by these two binomials, we will find that 4 and 4i are not like terms. Therefore, we can't simplify this expression.

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50 points for answer.

noname [10]

Answer:

Point C: (4, 0)

Step-by-step explanation:

Parallelograms are quadrilaterals with two pairs of parallel sides, this means they will have the same slope between two line segments.

point slope form between two points: y - y1 = m (x - x1)

point A (2, 6) and D (4,4):

slope: point form, 6 - 4 = m(2 - 4)

2 = -2m

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now that you know the change in position, apply this to vertice B to get the position of the final vertice.

B(2, 2)

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The final position of C vertice for parrallelogram A(2,6), B(2,2), D(4,4) will be C(4,0)

5 0

2 years ago

Read 2 more answers

Someone please help.

Alexxandr [17]

Hi there!

$f(x)+f(x+1)=4f(x)$

There are 3 parts to this equation:

f(x)

f(x+1)

4f(x)

We must first determine these three parts separately.

<u>1) f(x)</u>

We're given that $f(x)=3^x$ :

⇒ $f(x)=3^x$ :

<u>2) f(x+1)</u>

Now, we must find f(x+1). To do so, add 1 to x in the original function $f(x)=3^x$ :

⇒ $f(x+1)=3^x^+^1$

<u>3) 4f(x)</u>

To find 4f(x), multiply the original function $f(x)=3^x$ by 4:

$4f(x)=4*3^x$ :

<u>4) Put it all together</u>

Now, plug each of the three parts into the equation $f(x)+f(x+1)=4f(x)$ :

$f(x)+f(x+1)=4f(x)$

$3^x+3^x^+^1=4*3^x\\3^x+3^x*3=4*3^x$

Factor the left side

$3^x*(1+3)=4*3^x$

Divide both sides by 3^x

$1+3=4\\4=4$

Because this equation is true, $f(x)+f(x+1)=4f(x)$ is therefore true.

I hope this helps!

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