Ask question

Ask question

All categories

3 years ago

14

Will give brainliest to whoever answers this with a serious response. I have had no luck on it and the one answer I did get was

just somebody trolling.
These are fill in the blanks.
1. When I use line segments to connect the corresponding points of a pre-image and the image in a translation, the line segments are ____ and ____ because ____.
2. When I use line segments to connect the corresponding points of a pre-image and the image in a reflection, the line of reflection is the _____ of the segments because ____.
3. In a rotation, the corresponding points of the pre-image and the image are the same _____ from the center of rotation because _____.

1 answer:

antiseptic1488 [7]3 years ago

7 0

Answer:

what the question................

You might be interested in

Help if correct will give brainiest

kakasveta [241]

Answer:

x

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve the system of equations by substitution. What is the solution for x? (1 point)

Cerrena [4.2K]

       2x + y = 1
          2x - 2x + y = 1 - 2x
       y = 1 - 2x
       y = -2x + 1
       4x + 2y = -1
    4x + 2(-2x + 1) = -1
4x + 2(-2x) + 2(1) = -1
      4x - 4x + 2 = -1
         2 ≠ -1

The solution of the problem can't be a solution because they are both parallel lines, which means they have no solution.

8 0

3 years ago

Read 2 more answers

Rita has $b. Sharron has $11.50 less than Rita.

taurus [48]

Answer:

h = b - 11.50

Step-by-step explanation:

Sharron(h) has 11.50 less than Rita(b)

h = b - 11.50

3 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

The length of a board is 30.75 inches. Bradley cut the board into 3 smaller pieces that were all the same length. Which expressi

Harman [31]

Answer:

The length of each smaller piece, l=L/n inches

Step-by-step explanation:

This can be expressed as;

Total length=Length per piece×number of pieces

where;

The total length=L

length per piece=l

number of pieces=n

Substituting in the equation;

L=l×n

To get the length of each smaller piece;

l=L/n inches

solving;

l=30.75/3=10.25 inches

5 0

3 years ago