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Olenka [21]
2 years ago
7

What is the aswer ??????​

Mathematics
2 answers:
Katarina [22]2 years ago
8 0
The answer is prime number because it’s only two factor
svet-max [94.6K]2 years ago
3 0

Answer:

A prime numbers are numbers which have only two factor

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Calculate (6.3 × 10 ^5) × (2.5 × 10^ -2)
Talja [164]

Answer:

15750

Step-by-step explanation:

8 0
2 years ago
Find the value of x​
soldier1979 [14.2K]

Answer:

x = -14

Step-by-step explanation:

Look at the image attatched. I have labeled the angles for better explanation.

We know that angle 1 is 54 degrees as is rests on a straight line with its adjacent angle at 126 degrees. This means that angle 1 would be 180 - 126 degrees, or 54 degrees. We also know that angle 1 and 3 must be congruent as the sides of the triangle opposite those angles are congruent as well. This means that both those angles are 54 degrees. Since the sum of all angles in a triangle must equal 180 degrees, we can get that angle 4 is 180 - (2*54) degrees, or 72. Since angle two and angle 4 both lie on a straight line, they must add up to 180 degrees. This means that the value of angle 2 would be 180 - 72, or 108 degrees. Since angle 2 is also equal to x+122, we get the equation:

108 = x + 122.

We then solve this by getting:

x = 108 - 122

which gives us the answer of

x = -14

3 0
2 years ago
Read 2 more answers
What is the value of the expression 3² .(2³+4)/2²
Ber [7]

Answer:

27

Step-by-step explanation:

3^2(2^3+4)/2^2

3^2(8+4)/2^2

3^2(12)/2^2

9(12)/4

108/4

27

4 0
2 years ago
H = {(2, 5), (3, 5), (4, 5), (5, 5), (6, 5)} Is H a function and why?
Lorico [155]

Answer:

h is a function

Step-by-step explanation:i know that h is a function i just dont know why

7 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
erma4kov [3.2K]

Answer:

\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

Step-by-step explanation:

Given

5 tuples implies that:

n = 5

(h,i,j,k,m) implies that:

r = 5

Required

How many 5-tuples of integers (h, i, j, k,m) are there such thatn\ge h\ge i\ge j\ge k\ge m\ge 1

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed:  This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

^{n}C_r => ^{n + 4}C_5

^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}

^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}

Expand the numerator

^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

<u><em>Solved</em></u>

6 0
2 years ago
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