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maks197457 [2]
3 years ago
7

What is the area of this triangle in the coordinate plane?

Mathematics
2 answers:
Vikki [24]3 years ago
4 0

Answer:

The answer is 27.5

Step-by-step explanation:

Klio2033 [76]3 years ago
3 0
Hey. Let me help you on this one.

In order for us to solve this problem, we will be needing to find both length and width of the triangle on this coordinate plane. We will also need to know how to use the triangle area formula. 

I will be attaching an image containing the shown difference between a rectangle, and a triangle, and on how to understand why the area of a triangle is like this.

First of all, let's find the length of the triangle. It's 11 units, and we can determine that by counting up all of the units, or simply finding the difference between x-point 13 and 2, which is going to be 11.

Same applies to the width of the triangle. We will need to either count up all the units individually, or find a difference between a higher y-point and lower y-point. That difference is going to 5 units, since 9-4=5.

Now, let's use the formula for the triangle area and substitute the values.

S= \frac{a*b}{2}
S= \frac{11*5}{2}
S= \frac{55}{2}
S=27.5

Answer: Area of the triangle on the coordinate plane is 27.5 units squared.

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Which of the following statements are equivalent to the statement "price decreased by one third"?
N76 [4]
75% of what it before
4 0
3 years ago
1. Consider the rational numbers 4/13 and 3/10.
Murljashka [212]

A)4/13 would be the larger number since if you were to try to add them, 4/13 = 40/130 and 3/10 = 39/130, 40/130 > 39/130

B) A rational number between them would be 39.5/130.

5 0
3 years ago
There are 20 machines in a factory. 7 of the machines are defective.
adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

4 0
3 years ago
I need help ASAP plsss
Nutka1998 [239]

x would be 102° . hope it helps

4 0
3 years ago
Find the missing side length of the triangle.
Ilia_Sergeevich [38]

Answer:

c = 10

Explanation:

Use Pythagoras theorem: a² + b² = c²

where 'a' and 'b' are legs and 'c' is the hypotenuse (the longest side)

Here given: a = 8 cm, b = 6 cm, c = ?

Substituting values:

8² + 6² = c²

c² = 64 + 36

c² = 100

c = √100

c = 10

5 0
2 years ago
Read 2 more answers
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