What is the area of this triangle in the coordinate plane?

Mathematics

2 answers:

Vikki [24]3 years ago

4 0

Answer:

The answer is 27.5

Step-by-step explanation:

Klio2033 [76]3 years ago

3 0

Hey. Let me help you on this one.

In order for us to solve this problem, we will be needing to find both length and width of the triangle on this coordinate plane. We will also need to know how to use the triangle area formula.

I will be attaching an image containing the shown difference between a rectangle, and a triangle, and on how to understand why the area of a triangle is like this.

First of all, let's find the length of the triangle. It's 11 units, and we can determine that by counting up all of the units, or simply finding the difference between x-point 13 and 2, which is going to be 11.

Same applies to the width of the triangle. We will need to either count up all the units individually, or find a difference between a higher y-point and lower y-point. That difference is going to 5 units, since $9-4=5$ .

Now, let's use the formula for the triangle area and substitute the values.

$S= \frac{a*b}{2}$
$S= \frac{11*5}{2}$
$S= \frac{55}{2}$
$S=27.5$

Answer: Area of the triangle on the coordinate plane is 27.5 units squared.

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A doctor released the results of clinical trials for a vaccine to prevent a particular disease. In these clinical trials, 200,0

CaHeK987 [17]

Answer:

1) No, there is not enough evidence to support the claim that the vaccine was effective (P-value=0.104) .

The null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

being the subindex 1 for the experimental group and subindex 2 for the control group.

2) Test statistic z=-1.26

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the vaccine was effective.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

The significance level is 0.01.

The sample 1 (experimental group), of size n1=100000 has a proportion of p1=0.0002.

$p_1=X_1/n_1=21/100000=0.0002$

The sample 2 (control group), of size n2=100000 has a proportion of p2=0.0003.

$p_2=X_2/n_2=30/100000=0.0003$

The difference between proportions is (p1-p2)=-0.0001.

$p_d=p_1-p_2=0.0002-0.0003=-0.0001$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{21+30}{100000+100000}=\dfrac{51}{200000}=0.00026$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.00026*0.99974}{100000}+\dfrac{0.00026*0.99974}{100000}}\\\\\\s_{p1-p2}=\sqrt{0+0.0000000025}=\sqrt{0.0000000051}=0.000071$