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zaharov [31]
3 years ago
15

Which answer is the best explanation for how to check to see that the difference has been calculated correctly for this problem?

Mathematics
1 answer:
scoundrel [369]3 years ago
4 0
A. No, because if you add 76.5 and 4.32, you'll get 80.82 instead of 72.18.

B. Yes, because if you add 72.18 and 4.32 you'll get 76.5

C. No, because if you substract 4.32 from 72.18, you'll get 67.86 instead of 76.5.

D. No, because if you add 76.5 and 72.18, you'll get 144.65 instead of 4.32.

Correct answer: B
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The coefficients of the expression 2x^3 -5x^2 + x are:
Elden [556K]
2 , -5 , 1
those are the coefficients (C)
3 0
3 years ago
Read 2 more answers
The measure of an exterior angle of a regular polygon is 2x and the measure of an interior angle is 4x Find the measure of one i
kolbaska11 [484]

Answer:

Part a) The measure of an exterior angle is 60°

Part b) The measure of an interior angle is 120°

Step-by-step explanation:

step 1

Find the value of x

we know that

A regular polygon has equal sides and equal interior angles

The sum of an interior angle plus an exterior angle must be equal to 180 degrees (supplementary angles)

so

2x+4x=180

solve for x

6x=180

x=30

step 2

Find the measure of an exterior angle

2x

substitute the value of x

2x=2(30)=60\°

step 3

Find the measure of an interior angle

4x

substitute the value of x

4x=4(30)=120\°

In this problem the regular polygon is a hexagon

6 0
3 years ago
What is the overall charge for neon,oxide, copper, and tin ?
Finger [1]

Answer:

Neon is stable, hence has no charge.

Oxide (O2-) has a charge of -2

Cooper (Cu2+) has a charge of +2

Tin (Sn2+) has a charge of +2

hence overall charge = -2+2+2

<em><u>Over</u></em><em><u>all</u></em><em><u> </u></em><em><u>charge</u></em><em><u> </u></em>= +2

6 0
2 years ago
fire work a travels at the speed 300 ft/s firework b travels 240 ft/s. firework b is launched 0.25s before firework a. how many
storchak [24]

Answer:

Both fireworks  will explode after 1 seconds after firework b launches.

Step-by-step explanation:

Given:

Speed of fire work A= 300 ft/s

Speed of Firework B=240 ft/s

Time before which fire work b is launched =0.25s

To Find:

How many seconds after firework b launches will both fireworks explode=?

Solution:

Let t be the time(seconds) after which both the fireworks explode.

By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation

Firework A= 330(t)

Firework B=240(t)+240(0.25)

Since we need to know the same time after which they explode, we can equate both the equations

330(t) = 240(t)+240(0.25)

300(t)= 240(t)+60

300(t)-240(t)= 60

60(t)=60

t=\frac{60}{60}

t=1

7 0
3 years ago
HELP PLEASE
Hoochie [10]
If you had values instead of algebraic expressions, you would find the area of the patio and subtract that from the area of the yard. Even though you don't have values, you can still find the area and subtract by expanding and simplifying:
(8x + 2)(6x + 3)
8x × 6x = 48x²
8x × 3 = 24x
2 × 6x = 12x
2 × 3 = 6
So you get 48x² + 36x + 6 as your area of the yard

(x + 5)(3x + 1)
x × 3x = 3x²
x × 1 = x
5 × 3x = 15x
5 × 1 = 5
So the area of the patio is 3x² + 16x + 5

(48x² + 36x + 6) - (3x² + 16x + 5)
48x² - 3x² = 45x²
36x - 16x = 20x
6 - 5 = 1

So your answer is D. 45x² + 20x + 1. I hope this helps!

6 0
3 years ago
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