Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
(-1,2) is a solution
y>x
2>-1 is correct
in this case yes
x+y≥x
-1+2≥-1
1≥-1 is correct: Yes
in this case no
x+y≥y
1≥2
is not correct. No
Answer:
2 x 3 + 7 x 2 + 14 x + 12÷ 2x+ 3 = <u> x² +2x+ 4 </u>
Step-by-step explanation:
We multiply the first term 2x of the divisor with a term ( quotient) to get the first term of the dividend. Then we multiply the same term with each term of the divisor and subtract it from the dividend. The process continues unless we get the zero or a much smaller number than the dividend as the remainder
<u> x² +2x+ 4 </u>
2x+3 ║2 x 3 + 7 x 2 + 14 x + 12
2x³ + 3x²
<u> - - </u>
4x² +14x+12
4x²+ 6x
<u> - - </u>
8x+12
8x+12
<u> - - </u>
<u> 0 </u>
Answer:
3x - y + 
Step-by-step explanation:
Hooboy okay here we go.
1.) Rewrite the equation in the classic division method
3x³ + 2x²y - xy² 
2.) Divide using normal division rules, but it's super hard now 'cause there are letters involved. Basically, what can you multiply 3x³ by to get 9x⁴? 3x. So 3x is your first number. Then multiply everything else by 3x, and subtract
3x
3x³ + 2x²y - xy²
-(9x⁴ + 6x³y - 3x²y²)
= 0 - 3x³y - 2x²y² - 5x²y + xy³
Now lets do that again, see what happens. 3x³ times -y should get -3x³y
3x - y
3x³ + 2x²y - xy²
- (9x⁴ + 6x³y - 3x²y²)
= 0 - 3x³y - 2x²y² - 5x²y + xy³
- ( - 3x³y - 2x²y² + xy³)
= 0 + 0 - 5x²y + 0
So! From this information, we can know that the answer is 3x-y with a remainder of - 5x²y. How it's written is shown above, in "Answer"
