<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
60 out of 100 scores are passing scores, hence 
95% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
A similar problem is given at brainly.com/question/16807970
Remember, diameter = 2 x radius
Answer:
12,690 people are expected to vote for Mr Salva
Step-by-step explanation:
Here, we want to know the number of people that is expected to vote for a particular candidate in an election given that 54% of people surveyed had said they would vote for the candidate.
Now to calculate the number of people expected to vote for Mr Salva, what we need to do is to find the number out of 23,000 that actually represents a percentage of 54%
To do this, we find 54% of 23,500
mathematically, we have;
54/100 * 23,500
= 12,690
answer - true
all rectangles have four sides, and a shape is a quadrilateral if it has four sides
therefore, all rectangles are quadrilaterals
Use the midpoint formula,
(x1+x2/2,y1+y2/2)
(-1-5/2,1-3/2)
(-6/2,-2/2)
(-3,-1)
