Answer:
A it is linear because it has a constant rate of change
Answer:
Step-by-step explanation:
a: Wrong. The first thing that you have to notice is that the sum goes to infinity. If you want k=4 to be the last condition, then take out the 3 dots.
b: That's the answer.
c: wrong. You get a real mess when you let set k = 0. Try it on your calculator.
1 ÷ 0 = Watch carefully as your calculator mentally melts down.
d: wrong. It's just not right. The highest power is k^2. There is no way to get k^3
For the derivative tests method, assume that the sphere is centered at the origin, and consider the
circular projection of the sphere onto the xy-plane. An inscribed rectangular box is uniquely determined
1
by the xy-coordinate of its corner in the first octant, so we can compute the z coordinate of this corner
by
x2+y2+z2=r2 =⇒z= r2−(x2+y2).
Then the volume of a box with this coordinate for the corner is given by
V = (2x)(2y)(2z) = 8xy r2 − (x2 + y2),
and we need only maximize this on the domain x2 + y2 ≤ r2. Notice that the volume is zero on the
boundary of this domain, so we need only consider critical points contained inside the domain in order
to carry this optimization out.
For the method of Lagrange multipliers, we optimize V(x,y,z) = 8xyz subject to the constraint
x2 + y2 + z2 = r2<span>. </span>
-7=z/2+1
What you first need to do is to multiply both sides of the equation by 2
-14=z+2
Now you move the variable to the left side and change within it’s own sign
-z-14=2
Into
-z=2+14
Now you then add the numbers
-z=16
The last part you do is change the sign on both sides in this equation
z=-16
Therefore, z=-16 is your answer in number 16.
Shut up you try hard advertiser. Get deleted
