Answer:
p= 2.5
q= 7
Step-by-step explanation:
The lines should overlap to have infinite solutions, slopes should be same and y-intercepts should be same.
Equations in slope- intercept form:
6x-(2p-3)y-2q-3=0 ⇒ (2p-3)y= 6x -2q-3 ⇒ y= 6/(2p-3)x -(2q+3)/(2p-3)
12x-( 2p-1)y-5q+1=0 ⇒ (2p-1)y= 12x - 5q+1 ⇒ y=12/(2p-1)x - (5q-1)/(2p-1)
Slopes equal:
6/(2p-3)= 12/(2p-1)
6(2p-1)= 12(2p-3)
12p- 6= 24p - 36
12p= 30
p= 30/12
p= 2.5
y-intercepts equal:
(2q+3)/(2p-3)= (5q-1)/(2p-1)
(2q+3)/(2*2.5-3)= (5q-1)/(2*2.5-1)
(2q+3)/2= (5q-1)/4
4(2q+3)= 2(5q-1)
8q+12= 10q- 2
2q= 14
q= 7
Answer: 22 meters
<u>Step-by-step explanation:</u>
Draw a picture of a right triangle and label the height as 30 meters and the hypotenuse as 37 meters. Use the Pythagorean Theorem to find the base (the length of the shadow).
a² + b² = c²
x² + 30² = 37²
x² = 37² - 30²
x² = 1369 - 900
x² = 469
√x² = √469
x = 21.656
x ≈ 22
Checking the graph:- when x = 1 y = 0 so it cant be y = x^4
y = log4 x
is the same as
x = 4^y
Checking the graph, when x = 4, y = 1
Plugging these into the above 4 = 4^1 = 4
So the correct choice is first one
Answer:36 maybe
Step-by-step explanation:
4×3=12
12÷2=6
6×5=30
30+6=36