2 consecutive integers...x and x + 1
x + x + 1 < = 3
2x + 1 < = 3
2x < = 3 - 1
2x < = 2
x < = 1
x + 1 = 1 + 1 = 2.......the greatest possible value for the greatest integer is 2
Triangular prism
length of slanted side:
sqrt(3^2 + 4^2) = 5
SA = 2(1/2)(8)(3) + 8(12) + 2(5)(12) =240
V = (1/2)(8)(3)(12) = 144
cuboid
SA = 2(7x6) + 2(7x5) + 2(6x5) = 214
V = 7x6x5 = 210
The sum of n terms is given from the first term and the common ratio by

For your given values of a1=-11, r=-4, n=8, the sum of 8 terms is

Here is my process for solving this.
First I drew arrows that indicated I was moving the whole triangle 5 units to the left.
*Look at first attachment*
Then I drew another triangle using those new points. (The new triangle is in pink)
*Look at second attachment*
Then I drew arrows that moved this new triangle 4 units up. (The new arrows are in pink)
*Look at third attachment*
Then I drew the new triangle in blue using the new points.
*Look at fourth attachment*
Then I mirrored / reflected the triangle over the x axis (the horizontal line) In green.
*Look at fifth attachment*
The fifth attachment in green is the final product! Hope that helps.
Answer:
length: 12 ft
area: 72 square feet
Step-by-step explanation:
Let L represent the length of the mat in feet. Then L/2 is the width and the perimeter is ...
P = 36 = 2(L +L/2) = 3L . . . . . substitute the given information and simplify
12 = L . . . . . . divide by 3
The length of the mat is 12 ft.
__
The width of the mat is L/2 = 6 ft, and the area is the product of length and width.
Area = (12 ft)(6 ft) = 72 ft^2
The area of the mat is 72 square feet.