Answer:
x2 + 7x + x2 + 7x + 9 = 3
2. Solve the system of equations using the substitution method.
1 answer:
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Answer:
3/5 has the smallest denominator
Step-by-step explanation:
Question:
There exist infinitely many common fractions a/b , where a > 0 and b > 0 and for which 3/5 < a/b< 2/3. Of these common fractions, which has the smallest denominator? Express your answer as a common fraction.
Solution
A Common fraction is a rational number written in the form: a/b. Where a and b are both integers.
The denominator and numerator in this case are greater than zero. That is, they are non zeros.
The least common denominator (LCD) of two non- zero denominators is the smallest whole number that is divisible by each of the denominators.
To find the smallest denominator between 3/5 and 2/3, we would convert the fractions to equivalent fractions with a common denominator by finding their LCM (lowest common multiple).
When comparing two fractions with like denominators, the larger fraction is the one with the greater numerator and the smaller fraction is one with the smaller numerator.
In our solution after comparing, the smaller fraction would have the smallest denominator.
Find attached the solution.
Answer:
7miles
equations shown in work image below
work shown on the paper with more explanations because text is hard to write equations (sorry I used km but it is miles for your problem.)
:) please give a heart for thanks
and brainliest crown :)
Step-by-step explanation:
For both d=r*t
Each bikes to others house and leave at the same time so for Tony,
11 = 30*t
t= 11/30 hours
for Gerry,
11 = 25*t
t= 11/25 hours
Comparing these, with LCD,
Tony's time is 55/150
Gerry's time is 66/150
So Tony got to Gerry's house 11/150 hours quicker than Gerry got to Tony's house.
Now they turn around and head back toward each other. If they leave at the same exact time, the elapsed time for each until they met would be the same so t (for tony) = t (for gerry), but Tony got a head start.
We start the stopwatch when Gerry turns around 11/150 hours after Tony has turned around. If Gerry's time to where they meet from Tony's house t(gerry), then Tony's time from Gerry's house is t(gerry) + 11/150
