Which equation has only one solution?
1 answer:
Absolute value cannot be less than 0
Solve Absolute Value.<span><span>|<span>x−5</span>|</span>=<span>−1</span></span>No solutions.
<span>|<span><span>−6</span>−<span>2x</span></span>|</span>=8
<span>x=<span>−<span><span>7<span> or </span></span>x</span></span></span>=<span>1
</span>
<span>|<span><span>5x</span>+10</span>|</span>=10
<span>x=<span><span>0<span> or </span></span>x</span></span>=<span>−4</span>
<span>|<span><span>−<span>6x</span></span>+3</span>|</span>=<span>0
</span>
So your answer is D) |–6x + 3| = 0
Solve Absolute Value.<span><span>|<span>x−5</span>|</span>=<span>−1</span></span>No solutions.
<span>|<span><span>−6</span>−<span>2x</span></span>|</span>=8
<span>x=<span>−<span><span>7<span> or </span></span>x</span></span></span>=<span>1
</span>
<span>|<span><span>5x</span>+10</span>|</span>=10
<span>x=<span><span>0<span> or </span></span>x</span></span>=<span>−4</span>
<span>|<span><span>−<span>6x</span></span>+3</span>|</span>=<span>0
</span>
So your answer is D) |–6x + 3| = 0
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Then simplify b^2-4b+3=0
Then divide both numbers by 3 (b-3/3)(b-1/3)=0
If it doesn’t go in even like the second term then bring it before the B
Then equal both terms to 0 and solve