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3 years ago

Which equation has only one solution?

1 answer:

6 0

Absolute value cannot be less than 0
Solve Absolute Value.|x−5|=−1No solutions.

|−6−2x|=8
x=−7 or x=1

|5x+10|=10
x=0 or x=−4

|−6x+3|=0
 $x = \frac{1}{2}$

So your answer is D) |–6x + 3| = 0

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What is the center of a circle circumscribed about a triangle with vertices (−2, 2) ( 2, −2)and (6, 2)? A. (2, 2) B. (2, 0) C. (

grigory [225]

C. (0,2) if you plot these points correctly on a graph, the center is at 0,2. hope this helped.

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3 years ago

Given the function, d(t) = 50t, the variable t represents which of the following? Select all that apply. input output function i

Nikitich [7]

Answer:

Input

Independent variable

Step-by-step explanation:

we know that

Independent variables, are the values that can be changed or controlled in a given model or equation

Dependent variables, are the values that result from the independent variables

we have the function

$d(t)=50t$

In this problem

This is a proportional relationship between the variables d and t

The function d(t) represent the dependent variable or the output

The variable t represent the independent variable or input

5 0

3 years ago

Read 2 more answers

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago

What is the modulus of 2 – 3i?

Bas_tet [7]

What is the modulus of 2 – 3i?

8 0

3 years ago

If you start your break on 08:57 and you have 30 minutes of break when will your break end

VashaNatasha [74]

Answer:

9:27

Step-by-step explanation:

So to get to 9:00, we need 3 minutes so now you have 27 minutes left of break. Then, you add 27 and you get 9:27. I hope this helped and please mark me brainliest!

5 0

3 years ago

Read 2 more answers