To divide the following equation how would we revise the problem? 7.82 divided by .25

If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0

2 years ago

Points S, L, and P on this grid represent the locations of the school, the library, and the park

Vlad [161]

The distance, in units, from the school to the library and then the distance from the library to the park is 15 units.

<h3>What is the length of any line on the graph?</h3>

The distance or length of any line on the graph,

D = √{(x₂ - x₁)² + (y₂ - y₁)²}

where,

d = distance/length of the line between point 1 and 2,

(x₁ , y₁) = coordinate of point 1,

(x₂ , y₂) = coordinate of point 2,

The distance from school to the library is SL, therefore,

$\rm SL = \sqrt{(4-0)^2 + (1-4)^2} = 5\ units$

The distance from library to the park is LP, therefore,

$\rm LP = \sqrt{(-4-4)^2 + (-5-1)^2} = 10\ units$

Now, the distance, in units, from the school to the library and then the distance from the library to the park is 15 units (10 units + 5 units).

Learn more about the Length of the line:

brainly.com/question/16904935

#SPJ1

4 0

1 year ago

Round each number to the nearest whole number. What is the best estimate for the answer to 276.37 – 67.81? A. 209 B. 208.6

pav-90 [236]

A.209

<span>276.37 – 67.81 = 208.56
The 5 in .56 means round up.
This means 208.56 will turn into 209.</span>

8 0

3 years ago

Read 2 more answers

Here is number of goals a hockey team scored in each 10 matches 3 4 3 2 5 3 5 6 2 4 find the median