Answer:
We need a sample of size at least 13.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

90% confidence interval: (0.438, 0.642).
The proportion estimate is the halfway point of these two bounds. So

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?
We need a sample of size at least n.
n is found when M = 0.08. So






Rounding up
We need a sample of size at least 13.
1. Relation
2. Domain
3. Non linear
4. Range
5. Function
6. Linear
7. Y = mx + b is a linear equation where m is the slope and b is the y-intercept.
Here is the answer to the given problem above.
Here is the exponential function to model this situation:
<span>f(x) = 420(0.79)x
Now, solve with the given values.
</span><span>P(t)=420×(.79<span>)^t</span></span>
<span><span>P(5)=420×(.79<span>)^5</span>=129
So the answer would be 129 animals.
Hope this answer helps. Thanks for posting your question!</span></span>
Answer:
multiple choice?
Step-by-step explanation: