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3 years ago

A pile of 55 coins, consisting of nickels and dimes, is worth $3.90. find the number of each.

2 answers:

8 0

<span>N + D = 55 coins (1) (N stands for nickels, 5N + 10D = 390 cents (2) D stands for dimes) Simplify (2) by canceling the factor 5 in both sides: N + 2D = 78 (3) Subtract eq(1) from eq(3). You will get D = 78 - 55 = 23. Answer. 23 dimes and 55-23 = 32 nickels. Check. 23*10 + 32*5 = 390 cents</span>

kari74 [83]3 years ago

7 0

N + D = 55 coins (1) (N stands for nickels, 5N + 10D = 390 cents (2) D stands for dimes) Simplify (2) by canceling the factor 5 in both sides: N + 2D = 78 (3) Subtract eq(1) from eq(3). You will get D = 78 - 55 = 23. Answer. 23 dimes and 55-23 = 32 nickels. Check. 23*10 + 32*5 = 390 cent

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A special deck of cards has 3 blue cards, and 7 orange cards. The blue cards are numbered 1, 2, and 3. The orange cards are numb

brilliants [131]

Answer:

A.. Number of elements in the sample space is 10.

B.. Given that event B is card drawn is blue.

Step-by-step explanation:

Special deck has3 blue and 7 orange cards. The blue cards are numbered 1, 2 and 3. The orange cards are numbered 1, 2, 3, 4, 5, 6 and 7.

We draw one card randomly from the deck, the sample space is

S={b1, b2, b3, o1, o2, o3, o4, o4, o6, o7}

Where,

'b' represents blue card

And 'o' represents orange cards.

Number of elements in the sample space is 10.

Given that event B is card drawn is blue.

B={b1, b2, b3}.

7 0

3 years ago

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Alex_Xolod [135]

Answer:B

Step-by-step explanation:

5 0

3 years ago

Use the triangle below to find cos V.

Semenov [28]

Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

$cos\theta = \frac{Adjacent}{Hypotenuse}$

In this case:

$cos V= \frac{TV}{UV}$

Where

$TV = 6$

and

$UV^2 = TV^2 + TU^2$ -- Pythagoras

$UV^2 = 6^2 + 15^2$

$UV^2 = 261$

Take square roots

$UV = \sqrt{261$

$UV = \sqrt{9*29$

$UV = \sqrt{9} *\sqrt{29$

$UV = 3\sqrt{29$

So:

$cos V= \frac{TV}{UV}$

$cos\ V = \frac{6}{3\sqrt{29}}$

$cos\ V = \frac{2}{\sqrt{29}}$

Rationalize:

$cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}$

$cos\ V = \frac{2\sqrt{29}}{29}$

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3 years ago

Can someone help me with percents ?

denpristay [2]

The person HAD homework 75/100 or 75%

the remaining days he did NOT have homework , which is 25/100 or 25%

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3 years ago

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9x-7=-7 how do you solve this problem

borishaifa [10]

<span>9x-7=-7
You would add 7 to both sides because you want to get to the point were your variable is alone. 9x = 0 Then you would dicide each side by 9 because after doing this your variable would be alone. x = 0 would be your final answer.

YA BOIIIIIIIIIII, DEADPOOL IN THE HOUSE!

-Gives you a thumbs up- </span>

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3 years ago

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