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agasfer [191]
3 years ago
7

Find the quotient. 4^r ÷ 4^s

Mathematics
1 answer:
-BARSIC- [3]3 years ago
8 0
4^r-s is the answer
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Using the number line above, write the integer that each point represents
zloy xaker [14]

Answer:

E= -6

D=  4

B =- 4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
I just need the final answer. thanks! :)
aleksandr82 [10.1K]
4 miles per hour I think
5 0
3 years ago
​​​​​​​If K = F( A + B ) , find “ A ” if F = 2 , B = 3 , K = 10
Oxana [17]

Answer:

The value of A is 2

Step-by-step explanation:

F = 2 , B = 3 , K = 10

K = F( A + B )

10 = 2(A + 3)

10 = 2A + 6

Now, Subtract 6 from each side we get,

10 - 6 = 2A + 6 - 6

4 = 2A

2A = 4

Now, divide both side by 2 we get,

2A/2 = 4/2

A = 2

Thus, The value of A is 2

<h3><u>FOR V</u><u>ERIFICATION</u><u> ONLY</u> :-</h3>

K = F( A + B )

10 = 2(2 + 3)

10 = 2(5)

10 = 10

L.H.S = R.H.S

Hence Proved!

<u>-TheUnknownScientist</u><u> 72</u>

7 0
3 years ago
The sum of two numbers is 72 and their difference is 26. find two numbers?
Archy [21]

9514 1404 393

Answer:

  23, 49

Step-by-step explanation:

Let s represent the smaller of the two numbers. Then the larger is s+26, and the sum is ...

  s + (s+26) = 72

  2s = 72 -26

  s = (72 -26)/2 = 23

Then the larger number is

  s +26 = 49

The two numbers are 23 and 49.

_____

The reason we wrote the solution this way is to show you that the smaller number is half the difference between the given sum (72) and difference (26). This is the generic solution to a "sum and difference" problem. The smaller number is always half the difference of the give sum and difference. (Similarly, the larger is always half the sum of the given sum and difference.)

That is, the two numbers are always half the sum ± half the difference:

  72/2 ± 26/2 = {36+13, 36-13} = {49, 23}

7 0
3 years ago
Write (1/3i)-(-6+2/3i) as a complex number in standard form
Eddi Din [679]

Answer:

6+\frac{i}{3}

Step-by-step explanation:

\frac{1}{3\imath}-(-6+\frac{2}{3\imath})

\frac{1}{3\imath}+6-\frac{2}{3\imath}

taking like terms together

\frac{1}{3\imath}-\frac{2}{3\imath}+6

taking LCM

\frac{1-2}{3\imath}+6

\frac{-1}{3\imath}+6

taking LCM

\frac{-1+18\imath}{3\imath}

splitting the term

\frac{-1+18\imath}{3\imath}

splitting the term

-\frac{1}{3\imath}+\frac{18\imath}{3\imath}

-\frac{1\times3\imath}{3\imath \times \imath}+6

-\frac{i}{3\imath^2}+6

we know that

\imath^2=-1

putting this value in above equation

\frac{\imath}{3}+6

7 0
3 years ago
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