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Black_prince [1.1K]
3 years ago
5

Which new angle is created by extending one side of a triangle

Mathematics
2 answers:
8090 [49]3 years ago
7 0

Answer: The correct option is (C). an exterior angle.

Step-by-step explanation: We are to select the name of the new angle that is created by extending one side of a triangle.

Let ABC be a triangle as shown in the attached figure.

∠ABC, ∠ACB and ∠BAC are three interior angles of the triangle ABC.

Let us extend the side BC towards C to point D. The newly created angle is ∠ACD.

∠ACD is called the exterior angle of ΔABC.

Therefore, the newly created angle is an exterior angle.

Thus, option (C) is correct.

elena55 [62]3 years ago
3 0
It would be an exterior angle. I am sure, that this is the right answer.
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Find a statement that is equivalent to the absolute value equation |9x−9|=7.
Olegator [25]

Answer:9x-9=7 or 9x-9=-7

Step-by-step explanation:

An absolute value is the distance from zero, therefore the answer can not be negative. In this case, 9x-9=7 and 9x-9=-7 both work, because 7 and -7 are the same distance from zero.

8 0
3 years ago
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4 years ago
Do the following lengths form a right triangle? ​
Solnce55 [7]

Answer:

Yes, they do

Step-by-step explanation:

Because

6+8=14>9

6+9=15>8

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6 0
3 years ago
Polly's Polls asked 1850 second-year college students if they still had their original major. According to the colleges, 65% of
suter [353]

Answer:

The probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424

Step-by-step explanation:

The variable that assigns the value 1 if a person had its original major and 0 otherwise is a Bernoulli variable with paramenter 0.65. Since she asked the question to 1850 people, then the number of students that will have their original major is a Binomial random variable with parameters n = 1850, p = 0.65.

Since the sample is large enough, we can use the Central Limit Theorem to approximate that random variable to a Normal random variable, which we will denote X.

The parameters of X are determined with the mean and standard deviation of the Binomal that we are approximating. The mean is np = 1850*0.65 = 1202.5, and the standard deviation is √np(1-p) = √(1202.5*0.35) = 20.5152.

We want to know the probability that X is between 0.64*1850 = 1184 and 0.66*1850 = 1221 (that is, the percentage is between 64 and 66). In order to calculate this, we standarize X so that we can work with a standard normal random variable W ≈ N(0,1). The standarization is obtained by substracting the mean from X and dividing the result by the standard deviation, in other words

W = \frac{X-\lambda}{\sigma} = \frac{X-1202.5}{20.5152}

The values of the cummulative function of the standard normal variable W, which we will denote \phi are tabulated and they can be found in the attached file.

Now, we are ready to compute the probability that X is between 1184 and 1221. Remember that, since the standard random variable is symmetric through 0, then \phi(-z) = 1-\phi(z) for each positive value z.

P(1184 < X < 1221) = P(\frac{1184-1202.5}{20.5152} < \frac{X-1202.5}{20.5152} < \frac{1221-1202.5}{20.5152})\\ = P(-0.9018 < W < 0.9018) = \phi(0.9018) - \phi(-0.9018) = \phi(0.9018)-(1-\phi(0.9018))\\ = 2\phi(0.9018)-1 = 2*0.8212-1 = 0.6424

Therefore, the probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424.

Download pdf
4 0
4 years ago
PLEASE HELP ILL GIVE BRAINLIEST
DanielleElmas [232]

Option A:

(x-5)^{2}+(y-3)^{2}=16

Solution:

Given data:

Center of the circle is (5, 3).

Radius of the circle = 4

To find the equation of the circle:

The general form of the equation of a circle in centre-radius format is

(x-h)^{2}+(y-k)^{2}=r^{2}

where (h, k) is the centre of the circle and r is the radius of the circle.

Substitute the given values in the equation of a circle formula:

(x-5)^{2}+(y-3)^{2}=4^{2}

(x-5)^{2}+(y-3)^{2}=16

The equation of the given circle is (x-5)^{2}+(y-3)^{2}=16.

Hence Option A is the correct answer.

5 0
3 years ago
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