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2 years ago

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James works in a flower shop.He will put 36 tulips in vases for a wedding.He must use the same number of tulips in each vase.The

number of tulips in each vase must be greater than 1 and less than 10.How many tulips could be in each vase?

1 answer:

katrin [286]2 years ago

6 0

Start with the largest possible of 9 per vase. 36 by 9 is 4 vases. The next highest possible is 6 per vase, 36 by 6 is 6 vases.etc.

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Choose the correct response

lilavasa [31]

Answer:

f(2) = 9

Step-by-step explanation:

It's give in the question,

Two different functions are,

f(x) = 4x + 1

g(x) = -2x

Then we have to find the output value of function 'f' for the input value x = 2.

By substituting the value of x in the function 'f',

f(2) = 4(2) + 1

= 9

f(2) = 9

5 0

2 years ago

Please help me answer this

jonny [76]

The answer is 112 im pretty sure!

4 0

3 years ago

What does this equal to?

lesantik [10]

Answer:

x = 14

y = 7

z = 22

Step-by-step explanation:

x = # of cucumbers

y = # zucchini

z = # tomatoes

x + y + z = 43

2y = x or y = x/2

x + 8 = z

x + x/2 + x + 8 = 43

2x + x/2 = 35

4x + x = 70

5x = 70

x = 14

2y = 14

y = 7

14 + 8 = z

z = 22

Check if these variables are right:

14 + 7 + 22 = 43 ✔️

6 0

2 years ago

The pieces of a puzzle are placed half by Giulio, one fifth by Marco and Fabrizio in equal parts, while Michele arranges on the

denis23 [38]

Answer:

Not exactly sure but I think it should be 30 pieces

Step-by-step explanation:

3 0

1 year ago

Charlie's garage has a rectangular floor space. Its length is 3 times its width. Charlie extends the width of his garage to 6 m,

MAXImum [283]

Answer:

The percentage change is 140%

Step-by-step explanation:

Given

$L= 3W_1$ ---- initial dimension

$W_2 = 6m$ --- new width

$A_2 = 45m^2$ --- new dimension

Required

The percentage increment

The length remains constant because only the width is extended.

The new area is:

$Area =Length * Width$

$A_2=L * W_2$

Make L the subject

$L = \frac{A_2}{ W_2}$

Substitute values for A and W

$L = \frac{45m^2}{6m}$

$L = \frac{45m}{6}$

$L = 7.5m$ --- this is the length of the garden

Calculate the initial width:

$L= 3W_1$

Make W1 the subject

$W_1 = \frac{1}{3} * L$

$W_1 = \frac{1}{3} * 7.5$

$W_1 = 2.5$

So, the initial area is:

$A_1 = L_1 * W_1$

$A_1 = 2.5 * 7.5$

$A_1 = 18.75$

The percentage change in area is:

$\%A = \frac{A_2 - A_1}{A_1}$

$\%A = \frac{45 - 18.75}{18.75}$

$\%A = \frac{26.25}{18.75}$

$\%A = 1.4$

Express as percentage

$\%A = 1.4*100\%$

$\%A = 140\%$

4 0

3 years ago