We know that
At sea level, the height is 0 and
the pressure is 98 kilopascals
At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%
</span>i(100%-11.41%)/100----> (0.8859)
therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals
the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
Answer:
r = 105
Step-by-step explanation:
Given quadratic equation:
x² − 9x − 6
Quadratic formula is given by:
(-b ± √b² - 4ac) ÷ 2a
For the equation: x² - 9x - 6
a = 1, b = -9 and c = -6
Substitute in the quadratic formula:
(-b ± √b² - 4ac) ÷ 2a
(-(-9) ± √(-9)² - 4(1*-6)) ÷ 2*1
= 9 ± √105 / 2
The solution of x² − 9x − 6 is expressed as 9 plus or minus the square root of r, all over 2
Therefore, the value of r is 105
4(d-1), if you expand it gets 4d-4.
Answer:
121 assuming that 9
is the square root of 9
Step-by-step explanation:
I plugged it into my calculator, but use PEMDAS and you can get the answer.
Maybe search up Algebra calculator and type in the equation? idk
