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3 years ago

13

Sarah is making a pizza the diameter of the pizza is 8 inches what is the circumference of the pizza using 3.14 rounded to the n

earest tenth

2 answers:

Andreyy893 years ago

6 0

Answer:

Step-by-step explanation:

C=2πr

C=2π4

*If the diameter is 8, then the radius is 4.

C=25.1

hope its correct and hope it helps

egoroff_w [7]3 years ago

3 0

Circumference equals 2pir r=4in so 2(3.14)(4in)=25.12

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A home has a triangular backyard. The second angle of the triangle is 4degrees more than the first angle. The third angle is 8de

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A) The relationship between the amount of hours spent studying and the test scores increase with time in a positive direction showing a positive correlation.

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3 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

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Answer:

a) $\mu_{\bar x} =\mu = 276.1$

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b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago