Answer:
see explanation
Step-by-step explanation:
(a)
← divide numerator and denominator by 4
= = 0.8
(b)
→ divide numerator and denominator by 5
= = 0.7
(c)
← divide numerator and denominator by 4
= = 1.5
Square GYTD has vertices G(-4,3) ; Y(0, 3) , T(0, -1) and D(-4, -1) . square GYTD is translated 2 units left and 2 units up what
1 answer:
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Lagrange multipliers:
(if 
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(if 
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In the first octant, we assume
, so we can ignore the caveats above. Now,
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
.
We also need to check the boundary of the region, i.e. the intersection of
with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force 
, so the point we found is the only extremum.
In the first octant, we assume
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
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