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Zarrin [17]
3 years ago
5

Does the rule y=2•4^x represent an exponential function? Explain.

Mathematics
1 answer:
Andre45 [30]3 years ago
3 0

Yessssssssssssssssssssssssss

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HELP PLS!! BRAINLIEST
Schach [20]

Answer:

50 degrees

Step-by-step explanation:

Hope this helps and have a great day!!!

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3 years ago
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Write the fraction that names each part. Write a fraction in worlds and in number to name the shaded part.
Afina-wow [57]
Idk this answer because no triangles are shaded.

5 0
3 years ago
According to the Fundamental Theorem of Algebra, which polynomial function has exactly 8 roots?
natta225 [31]

Answer:

Polynomials of degree 8 have exactly 8 roots

Step-by-step explanation:

The Fundamental Theorem of Algebra states that every polynomial of degree n

P(x)=a_0+a_1x+a_2x^2+...+a_nx^n

with

a_n\neq 0

has exactly n roots.

But the roots may be complex numbers.

In your case n=8, so polynomials of degree 8 have exactly 8 roots.

The roots need not be different.

For example, for the polynomial

x^2-4x+4

x=2 is root twice.

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3 years ago
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Kaylis [27]

Step-by-step explanation:

The sum of three angle of any triangle is <u>1</u><u>8</u><u>0</u><u>°</u>....

8 0
2 years ago
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How do I estimate the square root and round to the nearest integer?
Troyanec [42]

The square root of a number y is a number x such that x^2=y

So, if a number is a perfect square, its square root is an integer. For example, the square root of 25 is 5, because 5^2=25.

If a number is not a perfect square, its square root is not an integer, which means that it is an irrational number, included between two integers.

If you want to find these two integers, you need to find two (consecutive) integers such that the first is "not enough", whereas the second is "too much".

Here's an example, suppose we want to find the square root of 20. We try some integers:

\left.\begin{array}{cc}1^2 = 1 & \text{Not Enough}\\2^2 = 4 & \text{Not Enough}\\3^2 = 9 & \text{Not Enough}\\4^2 = 16 & \text{Not Enough}\\5^2 =25 & \text{Too Much}\end{array}\right.

So, when we square 4 is slightly less than 20, and when we square 5 is slightly more than 20. This means that there must exist a number between 4 and 5 that, when squared, is exactly 20.

So, for sure 4 < \sqrt{20} < 5

In order to round to the nearest integer, we consider that 4^2=16 was 4 units away from the goal (20), while 5^2=25 was 5 units away from the goal. So, 4^2 is nearest to the goal than 5^2, and so we round

\sqrt{20}\approx 4

For the record, we have

\sqrt{20} \approx 4.472135955\ldots

so our approximation was correct.

3 0
3 years ago
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