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3 years ago

8

Pleaseee Help URGENTTTT

1 answer:

Marizza181 [45]3 years ago

7 0

Answer:

correct answer is b

Step-by-step explanation:

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For the given image and scale factor, which ordered pair is one of the pre-image vertices if the center of the pre-image is also

Virty [35]

Answer:

Step-by-step explanation:its the first one 3 5ths ,1

i just took the assignment

4 0

3 years ago

Read 2 more answers

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}$

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

7 0

2 years ago

Solve for equation x. <br> 3In(x)+2In(4)=In(128)

Serggg [28]

$Domain:\ x > 0\\\\3\ln(x)+2\ln(4)=\ln(128)\qquad\text{use}\ \lag_ab^n=n\log_ab\\\\\ln(x^3)+\ln(4^2)=\ln(128)\qquad\text{use}\ \log_ab+\ln_ac=\ln_a(bc)\\\\\ln(16x^3)=\ln(128)\iff16x^3=128\qquad\text{divide both sides by 16}\\\\x^3=8\to x=\sqrt[3]8\\\\\boxed{x=2}\in D$

3 0

3 years ago

What operation should be used to solve the equation 153=g+45

Advocard [28]

Answer:

Subtraction

Step-by-step explanation:

Subtraction

153 - 45 = g + 45 - 45

108 = g

3 0

3 years ago

X/6 + 2x/3 = 5 what is the value of x in the equation

ycow [4]

The value of x is 6 in the equation.

Step-by-step explanation:

Given equation is;

$\frac{x}{6}+\frac{2x}{3}=5$

Taking least common multiple

$\frac{x+4x}{6}=5$

Multiplying both sides by 6

$6*\frac{5x}{6}=5*6\\5x=30$

Dividing both sides by 5

$\frac{5x}{5}=\frac{30}{5}\\x=6$

The value of x is 6 in the equation.

Keywords: linear equation, fraction

Learn more about linear equations at:

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5 0

3 years ago