Answer:
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
d. z= 1.3322
Step-by-step explanation:
We formulate our hypothesis as
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
According to the given conditions
p`= 31/225= 0.1378
np`= 225 > 5
n q` = n (1-p`) = 225 ( 1- 31/225)= 193.995> 5
p = 0.4 x= 31 and n 225
c. Using the test statistic
z= p`- p / √pq/n
d. Putting the values
z= 0.1378- 0.11/ √0.11*0.89/225
z= 0.1378- 0.11/ √0.0979/225
z= 0.1378- 0.11/ 0.02085
z= 1.3322
at 5% significance level the z- value is ± 1.645 for one tailed test
The calculated value falls in the critical region so we reject our null hypothesis H0 : p ≤ 0.11 and accept Ha : p >0.11 and conclude that the data indicates that the 11% of the world's population is left-handed.
The rejection region is attached.
The P- value is calculated by finding the corresponding value of the probability of z from the z - table and subtracting it from 1.
which appears to be 0.95 and subtracting from 1 gives 0.04998
Since 25% is 1/4 divide 28 by 4 to get your answer of 9.5
That is an annuity and use the attached formula.
Total = 300 * [(1.055)^11 -1] / .055 -300
Total = 300 *
<span>
<span>
<span>
1.8020924036
</span>
</span>
</span>
-1 /.055 -300
Total = 300 *
<span>.8020924036 / .055 - 300
</span>Total = 300 *
<span>
<span>
<span>
14.5834982473
</span>
</span>
</span>
-300
Total =
<span>
<span>
<span>
4375.0494741818
</span>
</span>
</span>
-300
Total =
<span>4075.05
</span>
Answer:
your choice is correct
Step-by-step explanation:
The magnitude of the difference between the target amount and the actual amount will be no greater than the allowed error.
|x -34| ≤ 0.25
Distribute the negative sign

Combine like terms
-9x^2 + 7x^2 = -2x^2
9x - 3x = 6x
13 - 6 = 7

<u>Answer</u>
