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Natalija [7]
3 years ago
12

Write the number in scientific notation: 0.00000199?

Mathematics
2 answers:
faust18 [17]3 years ago
8 0

Answer:

i got 1.99 x 10^-6

rusak2 [61]3 years ago
5 0

Answer:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the  

10

. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

1.99

×

10

−

6

Step-by-step explanation:

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Mary bought 4 gallons of milk for $10.00. Jill bought 2.5 gallons for $6.00.
RoseWind [281]

Step-by-step explanation:  

In order to find the better buy, we must find the cheaper unit price or price per gallon.  To find the price per gallon, divide the cost by the number of gallons.

Mary

Mary bought 4 gallons for $11.

The price is $11 and the gallons are 4.

Jill

Jill bought 2.5 gallons for $7.25

The price is $7.25 and the gallons are 2.5

Better buy

Mary paid $2.75 per gallon and Jill paid $2.90 per gallon. 2.75 is less than 2.90, so Mary had the better buy.

3 0
2 years ago
What is 18/25 in simplest form
Anna35 [415]
It is already simplified because 18 cant go into 25
3 0
3 years ago
Read 2 more answers
What is 1/2 times 5/4?
Katen [24]

Answer:

1 x 5 = 5

2 x 4 = 8

5/8 is the answer.

3 0
3 years ago
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Choose the correct answer below. A. Increasing the level of confidence has no effect on the interval. B. Increasing the level of
murzikaleks [220]

Answer:

ME = t_{\alpha/2} \frac{s}{\sqrt{n}}

And the width for the confidence interval is given by:

Width =2ME=2t_{\alpha/2} \frac{s}{\sqrt{n}}

And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval t_{\alpha/2} would be higher and then the width of the interval would increase. So then the best answer for this case would be:

B. Increasing the level of confidence widens the interval.

Step-by-step explanation:

Let's assume that we have a parameter of interest \mu who represent for example the true mean for a population. And we can construct a confidence interval in order to estimate this parameter if we know the distribution for the statistic let's say \bar X and for this particular example the confidence interval is given by:

\bar X \pm ME

Where ME represent the margin of error for the estimation and this margin of error is given by:

ME = t_{\alpha/2} \frac{s}{\sqrt{n}}

And the width for the confidence interval is given by:

Width =2ME=2t_{\alpha/2} \frac{s}{\sqrt{n}}

And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval t_{\alpha/2} would be higher and then the width of the interval would increase. So then the best answer for this case would be:

B. Increasing the level of confidence widens the interval.

3 0
2 years ago
Its a multiple choice please answer.​
Tatiana [17]

Answer:

Last option (1/2)^3 = .125

Step-by-step explanation:

1/2 (1.035)^5 =0.579637

(2/3)^2 = 4/9 = .4444

.2^2/.3^2 = 0.04/0.09 = .44444

(1/2)^3 = 1/8 = .125

So we can clearly see the last one as the answer

8 0
3 years ago
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