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Fudgin [204]
3 years ago
8

Use the definition of continuity and the properties of limits to show that the function

Mathematics
1 answer:
Zepler [3.9K]3 years ago
7 0

Answer:

Applied the definition and the limit.

They had the same result, so the function is continuous.

Step-by-step explanation:

At function f(x) is continuous at x = a if:

\lim_{x \to a} f(x) = f(a)

In this question:

f(x) = x^{2} + 5(x-2)^{7}

At x = 3.

\lim_{x \to 3} x^{2} + 5(x-2)^{7} = 3^{2} + 5(3-2)^{7} = 14

f(3) = 3^{2} + 5(3-2)^{7} = 14

Since \lim_{x \to 3} f(x) = f(3), f(x) is continuous at x = 3.

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Solve for x 2(x-7)=0.2(x+2)+5.11
Kryger [21]

Answer:

Step-by-step explanation:

You start off by rewriting the equation:

2(x-7)=0.2(x+2)+5.11\\

Then you have to factor:

2x-14=0.2x+0.4+5.11

Then you subtract the 0.2x:

1.8x-14=0.4+5.11

Add the positives on the right:

1.8x-14=5.51

Add 14:

1.8x=19.51

Divide:

x=10.84

You get x is approximately equal to 10.84

3 0
3 years ago
Translate each equation into slope-intercept form. Then, state the slope and y-intercept . 4y=2x+20
likoan [24]

Answer:

           The slope-intercept form of the equation:  y = 0.5x + 5

           The slope:    m = 0.5

           The y-intercept:     b = 5

Step-by-step explanation:

Slope-intercept form is  y = mx + b, where m is the slope and b is y-intecept

4y = 2x + 20           {divide both sides by 4}

y = 0.5x + 5   ⇒   m = 0.5  and  b = 5

5 0
3 years ago
A car dealership sold 84 cars in April. The dealership wants to increase the number of cars sold by 25% in May. How many cars wi
Pie

Answer: 105 Cars

Step-by-step explanation: To get an increase of 25% you need to multiply 84 by .25 then add the product of that to 84 to get 105

4 0
3 years ago
Read 2 more answers
Help with this promblem please! :D
kondaur [170]

2/4 is equal to 3/6 because they both are equal to 1/2

6 0
3 years ago
Read 2 more answers
6th one....pls help me out​
zmey [24]

Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12n cannot end with the digit 0 or 5.

4 0
3 years ago
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