B is the answer!
Explanation:
m^2 n^2 fits into both, you can take m^2 n^2 out of it both.
m is a common factor since you can take m out of both but it’s not the greatest common factor.
2n & 2m wouldn’t even be a common factor bc there is no 2n or 2m in neither.
Answer:
7
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just don’t want to waste my time in case you don’t want me to :)
A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.
ONO THAT NOT THE ANSWER THIS IS [3,628,800] 10P10=10, AND 0!= 10 TIMES 9 TIMES 8 TIMES 7 TIMES 6 TIMES 5 TIMES 4 TIMES 3 TIMES 2 TIMES 1= 3,628,800.