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Sergio [31]
3 years ago
8

Please answer this please and thank you.

Mathematics
1 answer:
kvasek [131]3 years ago
4 0

Make sure you know how to do these you will be using this for the rest of your mathematical schooling.


.....................................................................

Answer:C

because the rest do not have the correct y intercept which is -3

y=mx+b

y=output

m=slope (growth rate)

x=input

b= y intercept

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Guys I need help ASAP! Please and thanks ​
Softa [21]

Answer:

The answer is 120) %0900

Step-by-step explanation:

the way of 5) the power of 6 is not a diagram

7 0
3 years ago
EASY MATH- MERRY X MAS :))))
balu736 [363]

Answer:

x-intercept means the advertising expense when the company's profit was zero dollars ⇒ D

Step-by-step explanation:

Let us solve the question

∵ P = -250x³ + 1,505x² - 300, for 0 < x < 6

∵ P is the profit in tens of thousands of dollars

∵ x is the advertising expense in tens of thousands of dollars  

∴ x is the independent variable

∴ P is the dependent variable

→ x-intercept means value x when P is 0

∵ The x-intercept is the value x at P = 0

∴ x-intercept means the advertising expense when the company's

   profit was zero dollars

4 0
3 years ago
What's .34 as a fraction
kondaur [170]
0.34 = 34/100
34/100 = 17/50

6 0
3 years ago
Read 2 more answers
2. Which of the following is(are) the solution(s) to 15x+2 - 8 ?
mixer [17]

Answer:

plz provide us with options

8 0
3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
3 years ago
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