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enot [183]
3 years ago
10

Consider the polynomial: StartFraction x Over 4 EndFraction – 2x5 + StartFraction x cubed Over 2 EndFraction + 1 Which polynomia

l represents the standard form of the original polynomial?
Mathematics
1 answer:
Phoenix [80]3 years ago
3 0

Answer:

- 2x^5+ 0x^4 +  \frac{x^3}{2} +0x^2+\frac{x}{4}  + 1

Step-by-step explanation:

Given

\frac{x}{4} - 2x^5 + \frac{x^3}{2} + 1

Required

The standard form of the polynomial

The general form of a polynomial is

ax^n + bx^{n-1} + cx^{n-2} +........+ k

Where k is a constant and the terms are arranged from biggest to smallest exponents

We start by rearranging the given polynomial

- 2x^5+ \frac{x^3}{2} +\frac{x}{4}  + 1

Given that the highest exponent of x is 5;

Let n = 5

Then we fix in the missing terms in terms of n

- 2x^5+ 0x^{n-1} +  \frac{x^3}{2} +0x^{n-3}+\frac{x}{4}  + 1

Substitute 5 for n

- 2x^5+ 0x^{5-1} +  \frac{x^3}{2} +0x^{5-3}+\frac{x}{4}  + 1

- 2x^5+ 0x^{4} +  \frac{x^3}{2} +0x^{2}+\frac{x}{4}  + 1

Hence, the standard form of the given polynomial is - 2x^5+ 0x^4 +  \frac{x^3}{2} +0x^2+\frac{x}{4}  + 1

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Answer:

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8 0
2 years ago
What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}?
anyanavicka [17]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

f( - 4) = 4( - 4) + 9 =  - 7

_________________________________

f( - 2) = 4( - 2) + 9 = 1

_________________________________

f(0) = 4(0) + 9 = 9

_________________________________

f(2) = 4(2) + 9 = 17

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Thus ;

R = { - 7 , 1 , 9 , 17 }

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

The correct answer is (( D )) .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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2 years ago
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